- 2073 Bhadra · 1+4 marks
Diode clamper circuit operation
Short answer
A diode clamper adds a DC level to an AC signal. In a positive clamper, the capacitor charges to Vm during the first negative half-cycle through the forward-biased diode; then the capacitor acts as a battery, shifting the output to Vin+Vm, clamping the negative peak near 0 V. The RC time constant must be large.
What is diode clamper? Describe the operation of diode clamper circuit.
A diode clamper (dc restorer) is a circuit that adds a dc level to an ac signal, shifting the whole waveform up or down without changing its shape. It consists of a capacitor, a diode and a resistor (and a battery if an extra shift is needed).
Positive clamper (shifts the waveform up)
Vin o---| |---+---o Vout
C |
D (anode to ground, cathode to output) [R across output]
|
GND o---------+---o
Take Vin = Vm sin ωt, an ideal diode, and an RC time constant much larger than the signal period.
Operation
- First negative half cycle: the output tries to go negative, so the diode is forward biased and conducts. The capacitor quickly charges through the diode to Vm (input-side plate negative), and Vout is held near 0 V.
- After that: the capacitor stays charged to about Vm and cannot discharge (the diode is off and R is large). It acts as a battery of Vm in series with the input.
- Output: Vout = Vin + Vm. The waveform now swings from 0 V to +2Vm; its negative peak is clamped at 0 V (−0.7 V for a real diode).
Vin Vm Vout 2Vm
---/\--/\--- /\ /\
---/--\/--\--- 0 ---/ \/ \--- 0
-Vm
Negative clamper
If the diode is reversed, the capacitor charges to Vm in the opposite polarity during the positive peak, and Vout = Vin − Vm. The positive peak is clamped at 0 V and the output swings from −2Vm to 0.
Biased clamper
A battery V in series with the diode moves the clamping level to ±V. The output is then Vin + (Vm ± V).
Applications: restoring the dc level in TV receivers, test equipment, and voltage multiplier circuits.
✓ Answer checked by Claude Opus 5.5 (high effort)
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