- 2071 Magh · 1+4 marks
RC low and high pass filters
Short answer
A filter passes desired frequency bands and attenuates others. A low-pass RC filter (output across C) has transfer H=1/(1+jωRC) and passes frequencies below cutoff fc=1/(2πRC); a high-pass RC filter (output across R) has transfer H=jωRC/(1+jωRC) and passes frequencies above fc. Magnitude at fc is 0.707 (−3 dB).
What do you mean by filter? Explain the RC low pass and high pass filters with corresponding transfer function and magnitude.
A filter is a circuit that allows signals in a certain range of frequencies to pass and attenuates signals of other frequencies. Both RC filters below have cut-off frequency fc = 1/(2πRC) (ωc = 1/RC), where |H| = 0.707 (−3 dB).
RC low pass filter
Vin o----[ R ]----+----o Vout
|
=== C
|
GND o-------------+----o GND
The output is taken across C.
- Transfer function: H(jω) = 1/(1 + jωRC)
- Magnitude: |H| = 1/√(1 + (ω/ωc)²), phase φ = −tan⁻¹(ω/ωc)
- |H| = 1 at low frequency, 0.707 at fc, and falls at 20 dB/decade above fc.
- Passes low frequencies; blocks high frequencies.
RC high pass filter
Vin o----| |----+----o Vout
C |
[ R ]
|
GND o-----------+----o GND
The output is taken across R.
- Transfer function: H(jω) = jωRC/(1 + jωRC)
- Magnitude: |H| = (ω/ωc)/√(1 + (ω/ωc)²), phase φ = 90° − tan⁻¹(ω/ωc)
- |H| rises at 20 dB/decade below fc, equals 0.707 at fc, and tends to 1 at high frequency.
- Passes high frequencies; blocks low frequencies and dc.
| Item | Low pass | High pass |
|---|---|---|
| Output across | C | R |
| Gain at f → 0 | 1 | 0 |
| Gain at f → ∞ | 0 | 1 |
| Phase | lag (0 to −90°) | lead (+90° to 0) |
✓ Answer checked by Claude Opus 5.5 (high effort)
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