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Op-amp properties and differentiator

Short answer

Ideal op-amp: infinite open-loop gain, infinite input resistance, zero output resistance, infinite bandwidth. Differentiator: input through C to inverting input, feedback Rf. Virtual ground: i = C dVin/dt = -Vo/Rf => Vo = -RfC dVin/dt. So output is derivative.

State any four important properties of ideal Op-Amp. Draw the circuit diagram of a differentiator using Op-Amp and show that the output is the derivative (differentiation) of the input signal.

Four properties of an ideal op-amp

  1. Infinite open-loop voltage gain.
  2. Infinite input resistance (zero input current).
  3. Zero output resistance.
  4. Infinite bandwidth, infinite CMRR and zero offset voltage.

Differentiator using op-amp

               +-----[ Rf ]-----+
               |                |
          C    |     |\         |
 Vin o----||---+-----|- \       |
                     |   >------+----o Vo
               +-----|+ /
               |     |/
              GND

The input Vin is connected through a capacitor C to the inverting input; the feedback resistor Rf connects the output to the inverting input; the non-inverting input is grounded.

Proof

  • The inverting input is at virtual ground, V− = 0.
  • Current through the capacitor: i = C d(Vin − 0)/dt = C dVin/dt.
  • No current enters the op-amp, so the same current flows through Rf: i = (0 − Vo)/Rf = −Vo/Rf.

Equating:

C dVin/dt = −Vo/Rf

Vo = −RfC dVin/dt

So the output is proportional to the derivative of the input, with a minus sign (180° phase shift). The scaling factor is the time constant RfC.

Example: for a sine input, Vin = Vm sin ωt, the output is Vo = −RfCωVm cos ωt. A square wave input gives spike (pulse) outputs, and a triangular input gives a square wave.

Practical note: the gain increases with frequency and amplifies noise, so a small resistor in series with C and a small capacitor in parallel with Rf are added to limit the high-frequency gain.

✓ Answer checked by Claude Opus 5.5 (high effort)

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