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- 2071 Magh · 2+4 marks
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Op-amp properties and differentiator
Short answer
Ideal op-amp: infinite open-loop gain, infinite input resistance, zero output resistance, infinite bandwidth. Differentiator: input through C to inverting input, feedback Rf. Virtual ground: i = C dVin/dt = -Vo/Rf => Vo = -RfC dVin/dt. So output is derivative.
State any four important properties of ideal Op-Amp. Draw the circuit diagram of a differentiator using Op-Amp and show that the output is the derivative (differentiation) of the input signal.
Four properties of an ideal op-amp
- Infinite open-loop voltage gain.
- Infinite input resistance (zero input current).
- Zero output resistance.
- Infinite bandwidth, infinite CMRR and zero offset voltage.
Differentiator using op-amp
+-----[ Rf ]-----+
| |
C | |\ |
Vin o----||---+-----|- \ |
| >------+----o Vo
+-----|+ /
| |/
GND
The input Vin is connected through a capacitor C to the inverting input; the feedback resistor Rf connects the output to the inverting input; the non-inverting input is grounded.
Proof
- The inverting input is at virtual ground, V− = 0.
- Current through the capacitor: i = C d(Vin − 0)/dt = C dVin/dt.
- No current enters the op-amp, so the same current flows through Rf: i = (0 − Vo)/Rf = −Vo/Rf.
Equating:
C dVin/dt = −Vo/Rf
Vo = −RfC dVin/dt
So the output is proportional to the derivative of the input, with a minus sign (180° phase shift). The scaling factor is the time constant RfC.
Example: for a sine input, Vin = Vm sin ωt, the output is Vo = −RfCωVm cos ωt. A square wave input gives spike (pulse) outputs, and a triangular input gives a square wave.
Practical note: the gain increases with frequency and amplifies noise, so a small resistor in series with C and a small capacitor in parallel with Rf are added to limit the high-frequency gain.
✓ Answer checked by Claude Opus 5.5 (high effort)
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