- 2068 Magh · 1.5+3.5 marks
Catalyst, catalysis; adsorption theory
Short answer
A catalyst alters reaction rate without being consumed, as in MnO₂ accelerating KClO₃ decomposition. The adsorption theory for heterogeneous catalysis involves reactant adsorption on active sites, bond weakening, surface reaction, and product desorption, like H₂ and C₂H₄ reacting on Ni to form C₂H₆.
Define catalyst and catalysis. Describe the adsorption theory of heterogeneous catalysis with a suitable example.
Catalyst and catalysis
A catalyst is a substance that changes the rate of a chemical reaction without being consumed in the reaction (its mass and chemical nature are the same at the end). The phenomenon is called catalysis. Example: MnO₂ speeds up the decomposition of KClO₃ to O₂.
Adsorption theory of heterogeneous catalysis
According to the adsorption theory (for heterogeneous catalysis), the catalyst works by adsorbing the reactant molecules on its surface. The steps are:
- Diffusion and adsorption: reactant molecules diffuse to the catalyst surface and are adsorbed on the active sites, so their concentration at the surface becomes high.
- Activation: adsorption weakens the bonds of the reactants (e.g. H–H breaks), forming activated, reactive species. Adsorption is exothermic, and the heat released helps to supply activation energy.
- Surface reaction: the activated adsorbed molecules, now close together, react to form the product.
- Desorption: the product molecules have little affinity for the surface; they leave the surface, which frees the active sites.
- The freed sites adsorb new reactant molecules and the cycle repeats.
H₂ C₂H₄ H–H C=C H H
↓ ↓ ↓ ↓ | |
▒▒▒▒▒▒▒▒▒▒▒ → ▒▒▒▒▒▒▒▒▒▒▒ → H–C–C–H (leaves)
Ni surface adsorbed, H–H | |
(adsorption) bond broken H H
Example: hydrogenation of ethene on nickel: C₂H₄ + H₂ → C₂H₆ (Ni). H₂ is adsorbed on Ni and splits into H atoms, ethene is also adsorbed, the H atoms add to the double bond, and ethane is desorbed.
The theory explains why a finely divided catalyst is more active (larger surface), why poisons stop catalysis (they occupy the active sites) and why promoters help (they increase the active surface).
✓ Answer checked by Claude Opus 5.5 (high effort)
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