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Complex formation by transition elements
Short answer
Transition metals form many complexes because of their small size, high charge density, vacant d orbitals accepting lone pairs, variable oxidation states, and ligand field stabilisation. Examples: [Fe(CN)6]4- and [Cu(NH3)4]2+.
Why do transition elements form significant number of complexes?
Transition elements form a large number of stable complexes because:
- Small size and high charge density: the ions are small and carry a high positive charge, so they strongly attract ligands (lone-pair donors).
- Vacant d orbitals of suitable energy: empty (n−1)d, ns and np orbitals are available to accept lone pairs from ligands and form coordinate (dative) bonds.
- Variable oxidation states allow different charges and so a variety of complexes.
- Ligand field stabilisation: the d-electrons gain extra stabilisation energy in the field of ligands.
Examples: [Fe(CN)₆]⁴⁻, [Cu(NH₃)₄]²⁺, [Ni(CO)₄], [Co(NH₃)₆]³⁺, [Ag(NH₃)₂]⁺. In contrast, s-block metals have large ions with low charge density and no d orbitals, so they form few complexes.
✓ Answer checked by Claude Opus 5.5 (high effort)
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