- 2072 Magh · 5 marks
d-d transition and origin of colour
Short answer
A d–d transition is an electron jump from the lower t2g to higher eg set of a ligand-field split d orbital, absorbing light. Colour arises because the absorbed wavelength matches Δo; the transmitted complementary colour is seen, e.g., [Ti(H2O)6]3+ absorbs green-yellow and appears violet.
What is meant by d to d transition? How does the color of the compound originate? Explain with d to d transition.
d–d transition: in a transition metal complex the five d orbitals are split by the ligand field into two sets of different energy. The jump of an electron from the lower set to the higher set by absorbing light is called a d–d transition.
Splitting of d orbitals (octahedral)
___ ___ e_g (dz², dx²−y²)
↑ Δo
___ ___ ___ t₂g (dxy, dyz, dxz)
In an isolated ion the five d orbitals have equal energy. When ligands approach, the repulsion raises the energy of e_g orbitals (which point at the ligands) more than the t₂g orbitals, giving the gap Δo.
Origin of colour
- White light falls on the complex.
- If Δo corresponds to a visible wavelength, an electron in t₂g absorbs that part of the light and moves to e_g.
- The remaining wavelengths are transmitted, and the eye sees the complementary colour.
Example: [Ti(H₂O)₆]³⁺ (d¹) absorbs green-yellow (≈ 500 nm) and appears violet; [Cu(H₂O)₄]²⁺ (d⁹) absorbs red-orange and appears blue.
Ions with d⁰ (Sc³⁺, Ti⁴⁺) or d¹⁰ (Zn²⁺, Cu⁺) cannot show d–d transitions, so they are colourless. The colour depends on the metal, its oxidation state and the ligands, since these change Δo.
✓ Answer checked by Claude Opus 5.5 (high effort)
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