- 2068 Magh · 4+1 marks
E² and SN² mechanisms; factor governing SN²
Short answer
E2: concerted β-H removal and leaving group departure, e.g. CH3CH2Br + KOH(alc) → ethene, rate = k[RX][base]. SN2: backside attack, one-step displacement with inversion, rate = k[RX][Nu−], e.g. CH3Br + OH− → CH3OH. A key factor governing SN2 is substrate steric hinderance: CH3 > 1° > 2° > 3°.
Explain the reaction mechanism involved in E² and SN² reactions. Mention the one factor governing SN² reaction.
E2 mechanism
Mechanism: E2 (one step, concerted).
B:⁻ H—CH₂—CH₂—Br → [B···H···CH₂···CH₂···Br]⁻‡ → B–H + CH₂=CH₂ + Br⁻
The base removes the β-hydrogen while the C–Br bond breaks and the π bond forms at the same time (the H and Br are anti-periplanar). Example: CH₃CH₂Br + KOH(alc) → CH₂=CH₂ + KBr + H₂O
- Rate = k[RX][Base]: second order (bimolecular).
- Needs a strong base and a high concentration of it; there is no intermediate.
SN2 mechanism
Mechanism: SN2 (one step, concerted).
HO⁻ + H₃C—Br → [HO···CH₃···Br]⁻‡ → HO—CH₃ + Br⁻
(transition state)
HO⁻ → C ← Br backside attack, 180° from Br
/|\
H H H inverted like an umbrella in the wind
Overall: CH₃Br + NaOH(aq) → CH₃OH + NaBr
- Rate = k[CH₃Br][OH⁻]: second order (bimolecular).
- The nucleophile attacks from the side opposite to the leaving group; the three H atoms flip over (Walden inversion).
- Reactivity order: CH₃X > 1° > 2° > 3° (steric hindrance).
Factor governing SN2
The structure of the substrate (steric hindrance) is the main factor: the reactivity falls as CH₃X > 1° > 2° > 3°, because bulky alkyl groups block the backside attack. (Other factors: nucleophile strength, leaving group, solvent.)
✓ Answer checked by Claude Opus 5.5 (high effort)
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