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Variable oxidation states of 3d elements
Short answer
The (n-1)d and ns electrons have similar energies, so both ns and a variable number of (n-1)d electrons can participate in bonding. Successive ionisation energies rise gradually, allowing multiple stable oxidation states. In the 3d series, states typically differ by one unit, e.g., Fe²⁺ and Fe³⁺.
Why do transition elements show variable oxidation states? Explain with reference to 3d series elements.
Transition elements show variable oxidation states because the (n−1)d and ns electrons have very nearly the same energy, so both the ns electrons and a variable number of (n−1)d electrons can take part in bonding. Successive ionisation energies rise gradually (unlike the sudden jump after the s-electrons in s-block metals), so ions of several charges can form. In the 3d series the states usually differ by one unit (e.g. Fe²⁺, Fe³⁺), unlike p-block elements whose states differ by two (Sn²⁺, Sn⁴⁺).
Oxidation states of 3d elements
| Element | Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
|---|---|---|---|---|---|---|---|---|---|---|
| Common oxidation states | +3 | +2, +3, +4 | +2, +3, +4, +5 | +2, +3, +6 | +2, +3, +4, +6, +7 | +2, +3 | +2, +3 | +2 | +1, +2 | +2 |
- Sc has one stable state (+3, loses 3 electrons to reach argon core) and Zn only +2 (3d¹⁰ stable), so they show little variability.
- The maximum state increases from Sc (+3) to Mn (+7), equal to the number of 3d + 4s electrons, then decreases after Mn because electrons are paired and the d orbitals become more stable.
- Examples: MnO₄⁻ (+7), Cr₂O₇²⁻ (+6), VO₂⁺ (+5).
Stability: the state with d⁰, d⁵ or d¹⁰ configuration is relatively stable (Sc³⁺, Mn²⁺, Fe³⁺, Zn²⁺). Higher states are stable in oxides and fluorides (high electronegativity), lower states in complexes with π-acceptor ligands such as CO.
✓ Answer checked by Claude Opus 5.5 (high effort)
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