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Steady state work vs steady flow; turbine, nozzle

Short answer

Work devices (turbine, compressor) exchange shaft work; flow devices (nozzle, throttle) do not. Adiabatic turbine: Ẇ_out = ṁ(h₁ − h₂) neglecting KE. Adiabatic nozzle: h₁ + V₁²/2 = h₂ + V₂²/2, so exit velocity V₂ ≈ √[2(h₁ − h₂)] for low inlet speed.

Differentiate between steady state work applications and steady state flow applications with examples. Also write the functions and governing equations for an adiabatic turbine and adiabatic nozzle.

In steady flow, the mass flow and the properties at each point do not vary with time (dm_cv/dt = 0, dE_cv/dt = 0), so Σṁ_i = Σṁ_e and Q̇ − Ẇ = ṁ[Δh + ΔKE + ΔPE]. Devices are grouped by whether they exchange shaft work.

BasisSteady state work devicesSteady state flow devices (no work)
Main purposeProduce or absorb shaft workChange velocity, pressure or temperature of the stream
Work termẆ ≠ 0Ẇ = 0
ExamplesTurbine, compressor, pump, fanNozzle, diffuser, throttle valve, heat exchanger, mixing chamber
Heat transferUsually negligible (adiabatic)Nozzle, throttle: negligible; heat exchanger: key effect
Governing equationw = (h₁ − h₂) for turbine (ΔKE, ΔPE neglected)Nozzle: h₁ + V₁²/2 = h₂ + V₂²/2

Adiabatic turbine

Function: expands high-pressure, high-temperature gas or steam to produce shaft work. Q = 0 and ΔPE ≈ 0:
Ẇ_out = ṁ [ (h₁ − h₂) + (V₁² − V₂²)/2 ]
The kinetic energy change is usually small, so w = h₁ − h₂.

Adiabatic nozzle

Function: accelerates the fluid by decreasing its pressure (increases its kinetic energy). Q = 0, W = 0, ΔPE = 0:
h₁ + V₁²/2 = h₂ + V₂²/2
V₂ = √[ V₁² + 2 (h₁ − h₂) ]; for inlet velocity ≈ 0, V₂ = √(2 Δh).

Mass balance for both: ṁ₁ = ṁ₂, ṁ = A V / v.

✓ Answer checked by Claude Opus 5.5 (high effort)

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