- 2071 Bhadra · 5 marks
Div and curl of grad φ, φ=log(x²+y²+z²)
Short answer
φ = log(x²+y²+z²): grad φ = 2r/(x²+y²+z²); div(grad φ) = 2/(x²+y²+z²); curl(grad φ) = 0.
If φ = log(x²+y²+z²), find div(grad φ) and curl(grad φ).
φ = log(x² + y² + z²). Let s = x² + y² + z².
Gradient
∂φ/∂x = 2x/s, ∂φ/∂y = 2y/s, ∂φ/∂z = 2z/s
grad φ = (2/s)(x i + y j + z k) = 2r/s
Divergence of grad φ
∂/∂x (2x/s) = 2/s − 2x(2x)/s² = 2/s − 4x²/s²
Similarly for y and z. Add:
div grad φ = 6/s − 4(x² + y² + z²)/s²
= 6/s − 4/s = 2/s
div(grad φ) = 2/(x² + y² + z²).
Curl of grad φ
grad φ = (2x/s, 2y/s, 2z/s). The x-component of the curl is
∂/∂y (2z/s) − ∂/∂z (2y/s)
= 2z(−2y/s²) − 2y(−2z/s²) = −4yz/s² + 4yz/s² = 0
The other components vanish in the same way (this is the identity curl grad φ = 0 for any twice-differentiable φ).
curl(grad φ) = 0.
✓ Answer checked by Claude Opus 5.5 (high effort)
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