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Relative velocity and acceleration

Short answer

Relative velocity of A with respect to B is the vector difference v_A/B = v_A - v_B; relative acceleration is similarly a_A/B = a_A - a_B. For example, car A east at 60 km/h and B north at 80 km/h gives v_A/B = 100 km/h at 53.1° south of east.

Define relative velocity and acceleration with suitable example.

Relative velocity

If two particles A and B have velocities v⃗A\vec v_A and v⃗B\vec v_B (both measured in a fixed frame), the relative velocity of A with respect to B is the velocity of A as seen by an observer moving with B:

v⃗A/B=v⃗A−v⃗B\vec v_{A/B}=\vec v_A-\vec v_B

Equivalently, v⃗A=v⃗B+v⃗A/B\vec v_A=\vec v_B+\vec v_{A/B}. It follows from the relative position r⃗A/B=r⃗A−r⃗B\vec r_{A/B}=\vec r_A-\vec r_B by differentiating.

Relative acceleration

In the same way, the relative acceleration of A with respect to B is

a⃗A/B=a⃗A−a⃗B\vec a_{A/B}=\vec a_A-\vec a_B

(valid when the observer on B translates without rotating). Note that v⃗B/A=−v⃗A/B\vec v_{B/A}=-\vec v_{A/B} and a⃗B/A=−a⃗A/B\vec a_{B/A}=-\vec a_{A/B}.

Example

Car A moves east at 60 km/h and car B moves north at 80 km/h. The velocity of A relative to B is

v⃗A/B=60i^−80j^ km/h,∣vA/B∣=602+802=100 km/h\vec v_{A/B}=60\hat i-80\hat j\ \text{km/h},\qquad |v_{A/B}|=\sqrt{60^2+80^2}=100\ \text{km/h}

at tan⁡−1(80/60)=53.1∘\tan^{-1}(80/60)=53.1^\circ south of east. A passenger in B sees A moving at 100 km/h in that direction. If A accelerates at 2i^2\hat i m/s2^2 and B at 1j^1\hat j m/s2^2, then a⃗A/B=2i^−1j^\vec a_{A/B}=2\hat i-1\hat j m/s2^2.

✓ Answer checked by Claude Opus 5.5 (high effort)

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