- Asked 4/16
- 2081 Bhadra · 2+6 marks
Define variable system; exploding projectile
Short answer
A variable system of particles gains or loses mass continuously. Momentum conservation for the explosion: 20(30) = 5 v_A cos45° + 15 v_B cos30°, 0 = 5 v_A sin45° – 15 v_B sin30°. Results: v_A = 62.12 m/s at 45° above horizontal, v_B = 29.28 m/s at 30° below.
Define variable system of particles. A 20 kg projectile is moving with a velocity of 30 m/s when it explodes into two fragments A and B, weighing 5 kg and 15 kg, respectively. Knowing that immediately after the explosion, fragments A and B travel in directions defined respectively by and , determine the velocity of each fragment. [Figure: 20 lb projectile moving right at ft/s; after explosion, 5 lb fragment A moves at above the horizontal and 15 lb fragment B at below the horizontal.]
Variable system of particles
A variable system of particles is one whose total mass changes with time because particles continuously join it or leave it, such as a rocket ejecting gas, a conveyor belt loaded with sand, or a chain being lifted from a heap. Its equation of motion is .
Exploding projectile
Internal forces of the explosion do not change the total momentum. Masses: kg, kg, kg, m/s (the numbers given in the question text; the figure shows the same arrangement in lb and ft/s).
A (5 kg)
/ 45 deg
v0 = 30 ---> *----------> x
\ 30 deg
B (15 kg)
x-direction:
y-direction:
Substituting (2) in (1):
Answer: m/s at above the horizontal; m/s at below the horizontal.
✓ Answer checked by Claude Opus 5.5 (high effort)
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