- 2069 Chaitra · 12 marks
Root locus of K/[s(s+1)(s²+4s+5)] with ξ = 0.5
Short answer
For ξ = 0.5, the dominant closed-loop poles are s = −0.288 ± j0.500 (ωn = 0.577 rad/s) with gain K ≈ 2.04. The system is stable for 0 < K < 8.
Plot the root loci for closed loop system with G(s) = K/[s(s+1)(s²+4s+5)], H(s) = 1. Also determine the dominant closed loop pole with ξ = 0.5.
Characteristic equation: .
1. Poles, zeros, branches
Poles: (). No zeros (). All four branches go to infinity.
2. Real-axis locus
Only between and .
3. Asymptotes
4. Breakaway point
Real root: . Gain there: . The other roots, , are not on the locus.
5. Angle of departure from
From : ; from : ; from : .
6. crossing (Routh)
| Row | Col 1 | Col 2 | Col 3 |
|---|---|---|---|
| 1 | 9 | ||
| 5 | 5 | ||
| 8 | |||
. Auxiliary equation: .
Sketch
|
|
... | ..
..... | ....
.... | ....
.....x .X..
...|
.# |
---------------------------x....*...x-------------
.# |
...|
.....x .X..
.... | ....
..... | ....
... | ..
|
|
-2 -1 0
x pole * breakaway (-0.393) X jw crossing (+-j1)
# zeta = 0.5 poles (-0.288 +- j0.5, K = 2.04)
- Branches from and break away at , curve toward the ±45° asymptotes, and cross the -axis at .
- Branches from leave at and follow the ±135° asymptotes.
7. Dominant closed-loop poles for ξ = 0.5
Constant-ξ line: from the negative real axis, i.e. . Search along it for . The solution is at , giving .
| From | Angle to | Distance |
|---|---|---|
| pole | 0.577 | |
| pole | 0.870 | |
| pole | 1.783 | |
| pole | 2.276 |
Gain from the magnitude criterion:
With , the other two closed-loop poles are at . They are about 7.7 times farther from the -axis than the dominant pair, so the pair at is truly dominant.
Answer: The dominant closed-loop poles for ξ = 0.5 are s = −0.288 ± j0.500 ( rad/s), at K ≈ 2.04. The system is stable for 0 < K < 8.
✓ Answer checked by Claude Opus 5.5 (high effort)
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