- 2076 Asoj · 10 marks
Root locus of k(s+2)/[s(s+1)(s²+8s+64)]
Short answer
G(s)H(s)=k(s+2)/[s(s+1)(s²+8s+64)]. Real-axis breakaway at -0.572, break-in at -3.51. Stable for 0<k<442.5. Marginally stable at k=442.5 with sustained oscillation frequency 7.50 rad/s.
Sketch Root locus plot for the system open loop transfer function G(s)H(s) = k(s+2)/[s(s+1)(s²+8s+64)]. Discuss the region for stability, instability and marginal stability. What is frequency of oscillation at the point of marginal stability?
Characteristic equation: .
1. Poles, zeros, branches
- Poles: (). Zero: ().
- There are 4 branches: one ends at and three go to infinity.
2. Real-axis locus
and .
3. Asymptotes
4. Breakaway / break-in points
Real roots: (), which is a breakaway between 0 and −1, and (), which is a break-in on . The other two roots are complex and are not on the locus.
5. Angle of departure from
Angles: from zero : ; from pole : ; from : ; from : .
6. Imaginary-axis crossing (Routh)
| Row | Col 1 | Col 2 | Col 3 |
|---|---|---|---|
| 1 | 72 | ||
| 9 | |||
Setting the row to zero: . Auxiliary equation: rad/s.
Shape of the locus
- The branches from and meet at and break away into the complex plane. They loop to the left and re-enter the real axis at the break-in point . From there, one branch goes right to the zero at and the other goes left to .
- The complex poles leave at (moving right), cross the -axis at , and follow the ±60° asymptotes.
| ....
| ....
.X...
x..............|
|
|
|
|
........... |
........................*.....o---x...x-----------
........... |
|
|
|
|
x..............|
.X...
| ....
| ....
-8 -4 -2 0
x pole o zero (-2) * break-in (-3.51)
X jw crossing (+-j7.5, k = 442.5)
Stability regions
| Range of | Nature |
|---|---|
| Stable (all poles in LHP) | |
| Marginally stable, poles at | |
| Unstable (two poles in RHP) |
Answer: Marginal stability at k = 442.5. The frequency of oscillation there is ω = 7.50 rad/s.
✓ Answer checked by Claude Opus 5.5 (high effort)
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