- 2080 Bhadra · 8 marks
Signal flow graph of G1–G3, H1–H3 block diagram
Short answer
Using Mason's gain formula with two forward paths (G1G2G3, G1H1G3) and five loops: C(s)/R(s) = G1 G3 (G2 + H1) / (1 + G2 H2 + G2 G3 H3 + G3 H1 H3 + G1 G2 G3 + G1 G3 H1).
Obtain the overall transfer function of given system by signal flow graph technique. [Figure: R(s) → summing point S1 (+, −) → G1 → summing point S2 (+, −) → summing point S3 (+, −) → node A. From node A: G2 → node B, and H1 (feedforward branch) going to summing point S4 (+). Node B → S4 (+) → G3 → C(s). From node B, H2 feeds back to S2 (−). From C(s), H3 feeds back to S3 (−). From C(s), unity feedback to S1 (−).]
In the signal flow graph method, each signal becomes a node and each block a branch; then Mason's gain formula gives the transfer function.
Signal flow graph
Nodes: = output of , = output of , = output of , = output of (node A), = node B, = output of , .
H1
+--------------+
| v
R -1-> x1 -G1-> x2 -1-> x3 -1-> x4 -G2-> x5 -1-> x6 -G3-> C
^ ^ ^ | |
| +-(-H2)-+---------+ |
| +-------(-H3)--------------+
+--------------------(-1)---------------------------+
Branches: (), (), (), (); all others as labelled.
Forward paths
- (through )
- (through the branch)
Individual loops
- ()
- ()
- ()
- ()
- ()
Non-touching loops
touches and at , and all others pass through /. So there are no non-touching pairs.
Cofactors
Both forward paths pass through , and , so they touch every loop: .
Mason's gain formula
Answer:
✓ Answer checked by Claude Opus 5.5 (high effort)
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