- 2067 Asar (old course) · 8 marks
State variable formulation of circuit with Vx and Vy
Short answer
Choose inductor current i_L and capacitor voltage v_C (positive at the node between R and L) as state variables, with inputs V_x, V_y. The state model is ẋ = A x + B u, where x = [i_L, v_C]^T, u = [V_x, V_y]^T, A = [[0, 1/L], [–1/C, –1/(RC)]], B = [[0, 1/L], [1/(RC), –1/(RC)]].
Write the state variable formulation of the circuit shown. [Figure: voltage source Vx (+ at top) in series with resistor R along the top wire; inductor L as a shunt branch to the bottom wire; then capacitor C in series along the top wire, connected to a voltage source Vy (+ at left) on the right side]
Circuit (as read from the figure). V_x in series with R feeds node N. The inductor L is connected from N to ground. The capacitor C is connected from N to a node P, and V_y is connected from P to ground (+ at P). Choose the inductor current i_L and capacitor voltage v_C (positive at N) as state variables; V_x and V_y are inputs.
Equations
KVL across the capacitor path: the voltage at node N equals the inductor voltage, and v_C = v_L − V_y, so
v_L = v_C + V_y
Inductor: L di_L/dt = v_L = v_C + V_y
KCL at N: current in R equals i_L plus the capacitor current.
i_R = (V_x − v_L)/R = (V_x − v_C − V_y)/R
C dv_C/dt = i_R − i_L = (V_x − v_C − V_y)/R − i_L
State equations
di_L/dt = (1/L) v_C + (1/L) V_y
dv_C/dt = −(1/C) i_L − (1/RC) v_C + (1/RC) V_x − (1/RC) V_y
Matrix form
| i_L' | | 0 1/L | | i_L | | 0 1/L | | Vx |
| | = | | | | + | | | |
| v_C' | | −1/C −1/(RC) | | v_C | | 1/(RC) −1/(RC) | | Vy |
ẋ = A x + B u with x = [i_L, v_C]ᵀ, u = [V_x, V_y]ᵀ,
A = [[0, 1/L], [−1/C, −1/RC]], B = [[0, 1/L], [1/RC, −1/RC]].
Outputs such as the resistor current are obtained from i_R = (V_x − v_C − V_y)/R. The system has two energy-storing elements, so the order is 2.
Check: the characteristic equation of A is s² + s/(RC) + 1/(LC) = 0, which is the standard parallel RLC (R, L, C) denominator, as expected.
✓ Answer checked by Claude Opus 5.5 (high effort)
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