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Electric dipole potential and field
Short answer
An electric dipole consists of two equal and opposite charges ±Q separated by distance d. Its dipole moment is p = Qd (direction −Q to +Q). For r≫d, V = p·a_r/(4πε₀ r²), and E = (p/(4πε₀ r³))(2cosθ a_r + sinθ a_θ).
What is an electric dipole? Derive the expressions for the potential and electric field due to a dipole at a distant point P (large compared to the separation of the charges). Explain the electric dipole moment.
Electric dipole
An electric dipole is a pair of equal and opposite point charges +Q and −Q separated by a small distance d. It is a source of an electric field that falls off faster (1/r³) than that of a single charge.
Potential at a far point P
Let the charges lie on the z-axis at z = ±d/2, with +Q above. P is at distance r from the centre, at angle θ from the dipole axis, and r ≫ d.
P
╱│╲
r₂ ╱ │ ╲ r₁ r₁ = distance from +Q
╱ │r ╲ r₂ = distance from −Q
−Q───●───+Q
←──d──→
V = (Q/4πε₀) (1/r₁ − 1/r₂) = (Q/4πε₀) (r₂ − r₁)/(r₁ r₂)
For r ≫ d the lines from the charges to P are almost parallel, so
r₂ − r₁ ≈ d cosθ, r₁ r₂ ≈ r²
V = Q d cosθ / (4πε₀ r²)
With the dipole moment p = Qd (magnitude Qd, directed from −Q to +Q), p · a_r = Qd cosθ, so
V = p · a_r / (4πε₀ r²) = p cosθ / (4πε₀ r²)
Electric field
Use E = −∇V in spherical coordinates:
E_r = −∂V/∂r = 2 p cosθ / (4πε₀ r³)
E_θ = −(1/r) ∂V/∂θ = p sinθ / (4πε₀ r³)
E_φ = −(1/(r sinθ)) ∂V/∂φ = 0
E = ( p / (4πε₀ r³) ) ( 2cosθ a_r + sinθ a_θ )
Special cases: on the axis (θ = 0), E = 2p / (4πε₀ r³) along a_r. On the equatorial plane (θ = 90°), E = p / (4πε₀ r³) along a_θ, i.e. opposite to p.
Dipole moment
The electric dipole moment p = Qd is a vector of magnitude charge × separation, directed from the negative to the positive charge. Unit: C·m. It measures the strength of the dipole. The potential and field depend only on the product Qd, not on Q and d separately. In an external field E, a dipole experiences a torque T = p × E.
✓ Answer checked by Claude Opus 5.5 (high effort)
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