- 2072 Chaitra · 2+1+4 marks
Barkhausen criteria and RC oscillator using op-amp
Short answer
Barkhausen criteria: |Aβ| = 1 and total phase shift 0°/360°. Yes, RC oscillators using op-amps satisfy this. For a phase-shift oscillator, f ≈ 0.065/(RC) and gain ≥ 29; for a Wien-bridge, f = 1/(2pi RC) and gain = 3.
State Barkhausen criteria for sinusoidal oscillator. Is this principle applicable to RC oscillator using op-Amp? Why? If yes, determine the frequency of oscillations and the gain of the amplifier circuit.
Barkhausen criteria: An amplifier with feedback produces sustained sinusoidal oscillation at the frequency for which the loop gain Aβ satisfies both:
- Magnitude condition: |Aβ| = 1 (loop gain is exactly unity)
- Phase condition: the total phase shift around the loop is 0° or 360° (positive feedback), that is, ∠Aβ = 0°, 360°, ...
Here A is the amplifier gain and β is the feedback factor.
Is the principle applicable to RC oscillators using an op-amp?
Yes. An RC oscillator is still a feedback system: an op-amp amplifier (gain A) and an RC feedback network (factor β). The oscillation condition is the same: loop gain |Aβ| = 1 with total phase shift 0° (360°) at one frequency. The RC network provides the frequency selectivity (it has the right phase only at one frequency), instead of an LC tank. The op-amp supplies the gain and needed phase (inverting or non-inverting).
Frequency and gain
Two common op-amp RC oscillators:
(a) RC phase-shift oscillator (inverting amplifier + three RC sections)
The three-section network gives 180° phase shift and an attenuation of 29 at one frequency. With the inverting amplifier of 180°, the total is 360°.
f = 1/(2π √6 RC) ≈ 0.065/(RC)
Required gain: |A| = Rf/R ≥ 29
(b) Wien-bridge oscillator (non-inverting amplifier + Wien network)
The network gives β = 1/3 and 0° phase at ω = 1/RC.
f = 1/(2π RC)
Required gain: A = 1 + Rf/R1 = 3 (Rf = 2 R1; slightly more than 3 to start the oscillation).
Example: R = 10 kΩ, C = 10 nF: phase-shift f = 650 Hz with gain 29; Wien f = 1.59 kHz with gain 3.
✓ Answer checked by Claude Opus 5.5 (high effort)
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