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Crossover distortion and its elimination
Short answer
Crossover distortion is flat zero-output near zero-crossing in class B when input is below VBE. Eliminate it by class AB biasing using diode drops or a VBE multiplier, or by applying negative feedback.
What is crossover distortion? How it can be eliminated?
Crossover distortion is the distortion of the output waveform near the zero-crossing in a class B push-pull amplifier. In the region where the input signal is smaller than the base-emitter turn-on voltage (about 0.6 to 0.7 V for silicon), neither transistor conducts, so the output is zero (a dead zone) for that part of the cycle.
Input Output (distorted)
/\ /\
/ \ / \
/ \ / ___ <- flat dead zone
------\------/------/ \--- at zero crossing
\ /
\ /
\/
When the input swings from positive to negative, the NPN turns off before the PNP turns on, so a flat step appears at the crossing. It is worst for small signals, and adds harmonics.
Methods to eliminate it
- Class AB biasing. Apply a small forward bias to each transistor so that both are just conducting (VBE ≈ 0.6 V) at zero signal. The conduction angle becomes slightly more than 180°, so one device takes over smoothly as the other turns off.
- Diode biasing. Place two forward-biased diodes (or a VBE multiplier transistor) between the bases of the complementary pair. The diode drops (about 1.2 to 1.4 V) bias both bases at the turn-on point and track temperature, which also prevents thermal runaway.
+VCC
|
[R1]
|----- B of Q1 (NPN)
--D1--
--D2--
|----- B of Q2 (PNP)
[R2]
|
-VCC
- Negative feedback. Include the output stage inside the feedback loop of an op-amp. The large loop gain reduces the dead zone.
The cost of class AB is a small idle current and a small drop in efficiency (still about 60 to 70 %).
✓ Answer checked by Claude Opus 5.5 (high effort)
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