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Ebers-Moll model and ac T-model of BJT

Short answer

Ebers-Moll model uses two diodes (DE, DC) and two current sources αFIF and αRIR. AC T-model replaces BJT with resistor re = VT/IE between base and emitter, and a current source α ie from collector to base. Suitable for CB, CC, and CE with RE.

Draw Ebers Moll model and ac equivalent T-model for BJT.

Ebers-Moll model

The large-signal model uses two diodes (the emitter-base and collector-base junctions) and two current sources that show the transport of carriers between the junctions.

  C o---+-----------+
        |           |
       ( ) αF·IF   DC | IR
        |           |
  B o---+-----------+
        |           |
       ( ) αR·IR   DE | IF
        |           |
  E o---+-----------+

Simplified form: DE (BE diode) carries IF = IES[exp(VBE/VT) - 1] and DC (BC diode) carries IR = ICS[exp(VBC/VT) - 1]. The collector gets αF IF from the emitter diode, and the emitter gets αR IR from the collector diode:

IC = αF IF - IR ,    IE = -(IF - αR IR) ,    IB = (1-αF) IF + (1-αR) IR

AC equivalent T-model

For small signals in the active region, the model is:

        C
        |
       ( )  α ie   (current source)
        |
 B -----+
        |
       re  (between base and emitter)
        |
        E
  • A resistor re = VT/IE (the dynamic resistance of the forward-biased BE junction) is placed between the emitter and the base.
  • The collector current source is α ie, directed from collector to base (equivalently ic = α ie).
  • The base current is ib = ie/(β+1) = (1-α) ie.
  • ro = VA/IC may be added in parallel with the source.

This model is best suited to circuits with resistance in the emitter (CB, CC and CE with RE), because re appears directly in the emitter path.

✓ Answer checked by Claude Opus 5.5 (high effort)

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