- 2080 Baisakh · 3+3 marks
Hybrid pi and T model, rπ and re
Short answer
rπ is base-emitter resistance in hybrid-π; re is emitter-base resistance in T-model. Since ie = (β+1)ib and vbe same, rπ = vbe/ib = (β+1)(vbe/ie) = (β+1)re. Also rπ = β/gm, re = VT/IE.
Draw Hybrid π and T model. Derive the relationship between rπ and re.
Hybrid-π model
The hybrid-π model is used for small signals in the active region. It has rπ between the base and the emitter, a voltage-controlled current source gm vπ between the collector and the emitter, and (optionally) ro in parallel with the source.
B o-----+ +---------+-----o C
| + | |
rπ vπ gm vπ (↓) ro
| - | |
E o-----+----------------+---------+-----o E
gm = IC/VT , rπ = vπ/ib = β/gm , ro = VA/IC.
T-model
The T-model is used when the base is the common terminal or when there is a resistor in the emitter. It has re between the emitter and the base, and a current source α ie between the collector and the base.
C o-------( ) α ie
|
B o-------+
|
re
|
E o-------+
re = VT/IE = α/gm.
Relation between rπ and re
rπ is the resistance seen at the base: rπ = vbe/ib. re is the resistance seen at the emitter: re = vbe/ie. The same vbe appears in both, and ie = (β+1) ib. Hence
rπ = vbe/ib = vbe/[ie/(β+1)] = (β+1)(vbe/ie)
rπ = (β+1) re
Also, rπ = β/gm and re = VT/IE = α/gm, so rπ/re = β/α = β + 1. For IC = 1 mA, β = 100: gm = 40 mA/V, rπ = 2.5 kΩ, re ≈ 24.8 Ω (rπ = 101 × 24.8 Ω).
✓ Answer checked by Claude Opus 5.5 (high effort)
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