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Darcy's law

Short answer

Darcy’s law states that discharge Q = K i A, where K is hydraulic conductivity, i hydraulic gradient, A cross-sectional area. It applies to laminar flow in saturated, homogeneous media with Reynolds number <1–10. Groundwater moves from high to low hydraulic head through pores.

State and explain Darcy's law and its applicability (how does water flow under the ground?).

Darcy's law states that the rate of flow of water through a porous medium is directly proportional to the hydraulic gradient and to the cross-sectional area normal to the flow.

Q=K i A=K ΔhL AQ = K\,i\,A = K\,\frac{\Delta h}{L}\,A

where QQ is the discharge (m3^3/s), KK is the coefficient of permeability (hydraulic conductivity, m/s), i=Δh/Li = \Delta h / L is the hydraulic gradient, and AA is the total cross-section area (m2^2). The Darcy velocity is v=Q/A=Kiv = Q/A = K i. The actual seepage velocity is vs=v/nv_s = v/n, where nn is the porosity.

   h1 ->  _________ L _________
         |   soil sample (A)   |-> Q
   h2 ->  ---------------------
   head loss  dh = h1 - h2

How water flows underground

Rain infiltrates, moves down through the unsaturated zone, and reaches the water table. In the saturated zone it moves slowly (cm/day to m/day) through pores and fractures, from high to low hydraulic head, until it comes out at springs, rivers or wells.

Applicability

  • Valid for laminar flow in saturated, homogeneous and isotropic media, with Reynolds number ReR_e less than about 1 (up to 10).
  • Not valid for very coarse gravel or fractured rock with turbulent flow, very high gradients, or very fine clay at very low gradient.

Example: K=1×10−4K = 1\times10^{-4} m/s, i=0.02i = 0.02, A=50A = 50 m2^2 gives Q=1×10−4×0.02×50=1×10−4Q = 1\times10^{-4}\times0.02\times50 = 1\times10^{-4} m3^3/s.

Answer: Q=1×10−4Q = 1\times10^{-4} m3^3/s, i.e. 0.1 litre/s.

✓ Answer checked by Claude Opus 5.5 (high effort)

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