- Practice · 6 marks
Kinetic energy and work of rigid body
Short answer
Kinetic energy of a rigid body in plane motion is T = ½ m v_G² + ½ I_G ω². The work-energy principle states T₁ + U₁→₂ = T₂. Forces doing no work on a rolling body include friction (contact point at rest) and normal reaction. Work of a couple is ∫ M dθ.
Derive the expression for the kinetic energy of a rigid body in plane motion. State the principle of work and energy for a rigid body and explain which forces do no work on a rolling body, and how the work of a couple is calculated.
Kinetic energy of a rigid body in plane motion
Let the body have mass , angular velocity , and let the mass centre G have velocity . A particle of mass at position relative to G has velocity (velocity of G plus velocity relative to G, magnitude ).
Since G is the mass centre, , so the middle term vanishes, and :
Special cases: pure translation ; rotation about a fixed point O, ; rolling without slipping, about the contact point.
Principle of work and energy for a rigid body
where is the work of all external forces and couples (and internal ones that do work, such as springs or friction between connected parts) between positions 1 and 2. For a system of connected bodies, add the kinetic energies of all bodies.
Work of forces and couples
- Force : at its point of application; weight: ; spring: .
- Couple : , which is for constant .
Forces that do no work
- Reactions at smooth fixed pins and smooth surfaces (perpendicular to motion).
- The friction force on a body rolling without slipping, because its point of application (the contact point) is instantaneously at rest, so no energy is dissipated. The normal reaction on a rolling body also does no work.
- Internal forces between particles of a rigid body (equal, opposite, no relative displacement).
If the body slips, the friction force does work (energy lost as heat).
✓ Answer checked by Claude Opus 5.5 (high effort)
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