- 2081 Chaitra (new course) · 2 marks
Analyticity of a function
Short answer
Writing sin z = sin x cosh y + i cos x sinh y, the partial derivatives are continuous and satisfy u_x=v_y, u_y=-v_x everywhere. Hence sin z is entire with derivative cos z.
For a complex variable, show that f(z) = sin z is analytic.
A function f(z) = u + iv is analytic in a region if u and v have continuous first partial derivatives there and satisfy the Cauchy–Riemann equations u_x = v_y and u_y = −v_x.
Write z = x + iy and use sin(x + iy) = sin x cos(iy) + cos x sin(iy) = sin x cosh y + i cos x sinh y.
u = sin x cosh y, v = cos x sinh y
u_x = cos x cosh y v_y = cos x cosh y → u_x = v_y ✓
u_y = sin x sinh y v_x = −sin x sinh y → u_y = −v_x ✓
The partial derivatives are continuous for all x, y, and the Cauchy–Riemann equations hold everywhere. Hence sin z is analytic everywhere (it is an entire function), and f'(z) = u_x + i v_x = cos x cosh y − i sin x sinh y = cos z.
✓ Answer checked by Claude Opus 5.5 (high effort)
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