- 2082 Chaitra (new course) · 2 marks
Classify a second order PDE
Short answer
For u_xx + x² u_yy = 0, discriminant B²−4AC = −4x². Hence elliptic where x≠0 (negative), and parabolic on the line x=0 (zero).
Write down the classification rules for a general second order partial differential equation and use them to classify the equation u_xx + x²u_yy = 0.
A general second order PDE in two variables is A u_xx + B u_xy + C u_yy + (lower order terms) = 0. Its type depends on the sign of the discriminant B² − 4AC at the point considered:
| Condition | Type | Example |
|---|---|---|
| B² − 4AC < 0 | Elliptic | Laplace equation |
| B² − 4AC = 0 | Parabolic | Heat equation |
| B² − 4AC > 0 | Hyperbolic | Wave equation |
Given: u_xx + x² u_yy = 0. Here A = 1, B = 0, C = x².
B² − 4AC = 0 − 4x² = −4x²
- For x ≠ 0, B² − 4AC < 0, so the equation is elliptic.
- On the line x = 0, B² − 4AC = 0, so it is parabolic there (the equation degenerates to u_xx = 0).
Answer: elliptic everywhere except on the y-axis (x = 0), where it is parabolic.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Classify a second order PDE · Mathematics III, chapter 4
- Solve a partial differential equation · Mathematics III, chapter 4
- Solve a partial differential equation · Mathematics III, chapter 4
- Lagrange's method for a PDE · Mathematics III, chapter 4
- General electrical rules for installation and wiring · Industrial Power Distribution and Illumination, chapter 1 · asked 3×
- First and second order finite difference schemes · Computational Techniques in Civil Engineering, chapter 5 · asked 2×
- Program for RK-4 second order IVP · Numerical Method, chapter 6
- General safety rules in a machine workshop · Workshop Technology, chapter 1