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Half range cosine series: x
Short answer
The half-range cosine series on (0,2) is x = 1 − (8/π²) Σ_{n odd} (1/n²) cos(nπx/2). a₀=2, aₙ=4((−1)ⁿ−1)/(n²π²) giving −8/(n²π²) for odd n and 0 for even n.
Express f(x) = x as a cosine half range series in 0 < x < 2.
The half range cosine series on (0, L) is f(x) = a₀/2 + Σ aₙ cos(nπx/L), where a₀ = (2/L)∫₀ᴸ f dx and aₙ = (2/L)∫₀ᴸ f cos(nπx/L) dx. Here L = 2 (the function is extended as an even function).
Coefficients for f(x) = x:
a₀ = (2/2)∫₀² x dx = [x²/2]₀² = 2
aₙ = ∫₀² x cos(nπx/2) dx
= [ x·(2/nπ) sin(nπx/2) ]₀² − (2/nπ)∫₀² sin(nπx/2) dx
= 0 + (2/nπ)(2/nπ)[cos(nπx/2)]₀²
= (4/n²π²)(cos nπ − 1)
= 4((−1)ⁿ − 1)/(n²π²)
- n even: aₙ = 0
- n odd: aₙ = −8/(n²π²)
Series
x = 1 − (8/π²) Σ (n odd) cos(nπx/2) / n², 0 < x < 2
= 1 − (8/π²)[ cos(πx/2) + cos(3πx/2)/3² + cos(5πx/2)/5² + … ]
Check: at x = 0 the series gives 1 − (8/π²)(1 + 1/9 + 1/25 + …) = 1 − (8/π²)(π²/8) = 0.
✓ Answer checked by Claude Opus 5.5 (high effort)
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