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Point of contraflexure; w-V-M relation

Short answer

A point of contraflexure is where bending moment changes sign, passing through zero. For a beam element, dV/dx = -w and dM/dx = V, so d²M/dx² = -w. The rate of shear force change equals negative load intensity; the rate of bending moment change equals shear force.

Define point of contraflexure. Derive the relationship between rate of loading, Shear force and Bending moment.

Point of contraflexure

A point of contraflexure (inflexion point) is a point on a beam where the bending moment changes sign (passes through zero), so the beam's curvature changes from sagging to hogging or vice versa. The bending moment there is zero, but a zero moment does not always mean contraflexure: the moment must also change sign.

Relation between loading rate, shear force and bending moment

Take an element of length dxdx of a beam on which the load intensity is ww per unit length, acting downward. VV and MM act on the left face; V+dVV + dV and M+dMM + dM act on the right face.

          w
   ↓ ↓ ↓ ↓ ↓ ↓
  M ┌─────────┐ M + dM
 V ↑│         │↓ V + dV
    └─────────┘
        dx

Vertical equilibrium

V−w dx−(V+dV)=0  ⇒  dVdx=−wV - w\,dx - (V + dV) = 0 \;\Rightarrow\; \frac{dV}{dx} = -w

Moment equilibrium about the right face (the term w dx2/2w\,dx^2/2 is negligible):

M+V dx−w dx⋅dx2−(M+dM)=0  ⇒  dMdx=VM + V\,dx - w\,dx\cdot\frac{dx}{2} - (M + dM) = 0 \;\Rightarrow\; \frac{dM}{dx} = V

Combining:

d2Mdx2=dVdx=−w\frac{d^2M}{dx^2} = \frac{dV}{dx} = -w

Meaning: the rate of change of shear force equals the negative of the load intensity, and the rate of change of bending moment equals the shear force. The moment is a maximum where V=0V = 0. A point of contraflexure occurs where M=0M = 0 and MM changes sign, i.e. where the curvature of the elastic curve (1/R=M/EI1/R = M/EI) changes sign. Where there is no load near that point (w=0w = 0), it is simply where the straight-line BMD crosses the axis.

✓ Answer checked by Claude Opus 5.5 (high effort)

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