- 2081 Bhadra · 2+6 marks
Flexural rigidity; T-beam bending stresses (60 kN loads)
Short answer
Flexural rigidity EI resists bending. M_max=60 kN·m. Section centroid 13.21 cm from bottom, I=5900.3 cm⁴. Maximum tensile stress (bottom) 134.4 MPa, compressive stress (top) 69.0 MPa.
Explain flexural rigidity and its importance. A beam is loaded as shown in figure. Determine maximum tensile and compressive bending stress developed in the beam. [Figure: simply supported beam A-B-C-D with a hinge at A and a roller at D; two 60 kN downward loads at B and C; A to B 1 m, B to C 1.5 m, C to D 1 m. Cross-section: inverted T-shape with a top flange 7.5 cm + 7.5 cm either side of the web (web width 5 cm), web height 15 cm and flange thickness 5 cm as marked.]
Flexural rigidity
Flexural rigidity is the product of Young's modulus and the moment of inertia of the section about the neutral axis. It measures the resistance of a beam to bending: from , the curvature and deflection of a beam are inversely proportional to .
Importance: a larger gives smaller deflection and curvature for the same loading. It is used to check deflection limits, to compare sections (deep sections have large ), and it appears in the deflection and column formulas (, ).
Bending stresses in the beam
Reading of the figure: simply supported beam with span m and two 60 kN loads at B (1 m from A) and C (1 m from D). The T-section has a flange cm wide and 5 cm thick, and a web 5 cm wide and 15 cm deep (total depth 20 cm). The flange is taken at the top (if the flange is at the bottom, the tensile and compressive values below are interchanged).
Reactions and maximum moment: by symmetry kN. The maximum moment is constant between B and C:
Centroid (from the bottom of the web):
Moment of inertia about the neutral axis:
Stresses (, N·cm):
Answer: maximum tensile stress N/mm² (bottom of the web); maximum compressive stress N/mm² (top of the flange).
✓ Answer checked by Claude Opus 5.5 (high effort)
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