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Corrections in linear measurement

Short answer

Corrections for standardisation (tape length), temperature, pull, sag (negative), slope (negative), alignment and reduction to mean sea level. The true length is the measured length plus the sum of all corrections.

What are the corrections applied in linear measurement? Explain briefly.

When a tape or chain is used in the field, the measured length differs from the true horizontal length because of the tape's condition and the field conditions. The following corrections are applied. Let LL be the measured length.

1. Correction for incorrect length of tape (standardisation)

Ca=L (l′−l)lC_a = \frac{L\,(l' - l)}{l}

where l′l' is the actual tape length and ll the nominal length. It is positive if the tape is too long, negative if too short.

2. Correction for temperature

Ct=α (Tm−T0) LC_t = \alpha\,(T_m - T_0)\,L

where α\alpha is the coefficient of linear expansion, TmT_m the mean field temperature and T0T_0 the standard temperature. Positive if Tm>T0T_m > T_0.

3. Correction for pull (tension)

Cp=(P−P0) LA EC_p = \frac{(P - P_0)\,L}{A\,E}

PP = applied pull, P0P_0 = standard pull, AA = cross-sectional area, EE = Young's modulus. Positive if P>P0P > P_0.

4. Correction for sag

Cs=−L w2 ls224 P2=−n W2 ls24 P2C_s = -\frac{L\,w^{2}\,l_s^{2}}{24\,P^{2}} = -\frac{n\,W^{2}\,l_s}{24\,P^{2}}

where ww = weight per metre, lsl_s = length of each span between supports, W=w lsW = w\,l_s. It is always negative when the tape is standardised on the flat and used suspended.

5. Correction for slope

Ch=−h22L(approx.)orCh=−L(1−cos⁡θ)C_h = -\frac{h^{2}}{2L} \quad\text{(approx.)} \qquad\text{or}\qquad C_h = -L(1-\cos\theta)

where hh is the height difference. Always negative.

6. Correction for alignment (tape not in line): always negative.

7. Reduction to mean sea level

Cmsl=−L hRC_{msl} = -\frac{L\,h}{R}

where hh is the elevation above MSL and RR is the radius of the earth (6370 km). Negative.

True length =L+Ca+Ct+Cp+Cs+Ch+Cmsl= L + C_a + C_t + C_p + C_s + C_h + C_{msl}.

✓ Answer checked by Claude Opus 5.5 (high effort)

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