- 2068 Chaitra · 2+5 marks
Chopper classification; step-down chopper RL load
Short answer
Choppers are classed by output voltage (buck, boost, buck-boost), quadrant (A–E), and commutation. A step-down chopper with RL load alternately connects supply via a switch and freewheels inductor current through a diode; average output voltage Vo = k·Vs, and ripple depends on L and frequency.
Classify chopper. Explain principle of step-down chopper with RL load.
Classification of choppers
- By output voltage level:
- Step-down chopper (buck): Vo = k·Vs < Vs
- Step-up chopper (boost): Vo = Vs/(1 − k) > Vs
- Step-up/down chopper (buck-boost)
- By quadrant of operation (direction of Vo and Io):
- Class A: first quadrant (+V, +I)
- Class B: second quadrant (+V, −I), regenerative
- Class C: two-quadrant, I and II (current reversible)
- Class D: two-quadrant, I and IV (voltage reversible)
- Class E: four-quadrant
- By commutation: voltage-commutated, current-commutated, load-commutated, impulse-commutated.
Step-down chopper with RL load
CH
+Vs --/ --+--------+
| R
FD L
| E (0 if pure RL)
− ------+--------+
Mode 1 – CH ON (0 < t < Ton): Load is connected to Vs; FD reverse biased. Current rises exponentially from I1 to I2:
Vs = R·i + L·di/dt + E
i = I1·e^(−t/τ) + ((Vs − E)/R)(1 − e^(−t/τ)), τ = L/R
Mode 2 – CH OFF (0 < t < Toff): Inductor energy keeps current flowing through FD; vo = 0. Current decays from I2 to I1:
0 = R·i + L·di/dt + E
i = I2·e^(−t/τ) − (E/R)(1 − e^(−t/τ))
Waveforms (continuous current):
vo Vs |‾‾‾‾|____|‾‾‾‾|____
0 Ton T
io I2 | /\ /\
I1 |__/ \___/ \___
(rises: CH)(falls: FD)
Output relations:
Vo = (1/T)∫₀^(Ton) Vs dt = k·Vs
Io = (k·Vs − E)/R
ΔI = I2 − I1, maximum at k = 0.5:
ΔImax = (Vs/R)·tanh(R/(4fL)) ≈ Vs/(4fL)
Higher chopping frequency or larger L gives smoother current. Used for DC motor speed control.
✓ Answer checked by Claude Opus 5.5 (high effort)
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