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Chopper classification; step-down chopper RL load

Short answer

Choppers are classed by output voltage (buck, boost, buck-boost), quadrant (A–E), and commutation. A step-down chopper with RL load alternately connects supply via a switch and freewheels inductor current through a diode; average output voltage Vo = k·Vs, and ripple depends on L and frequency.

Classify chopper. Explain principle of step-down chopper with RL load.

Classification of choppers

  1. By output voltage level:
    • Step-down chopper (buck): Vo = k·Vs < Vs
    • Step-up chopper (boost): Vo = Vs/(1 − k) > Vs
    • Step-up/down chopper (buck-boost)
  2. By quadrant of operation (direction of Vo and Io):
    • Class A: first quadrant (+V, +I)
    • Class B: second quadrant (+V, −I), regenerative
    • Class C: two-quadrant, I and II (current reversible)
    • Class D: two-quadrant, I and IV (voltage reversible)
    • Class E: four-quadrant
  3. By commutation: voltage-commutated, current-commutated, load-commutated, impulse-commutated.

Step-down chopper with RL load

       CH
 +Vs --/ --+--------+
           |        R
           FD       L
           |        E (0 if pure RL)
 −   ------+--------+

Mode 1 – CH ON (0 < t < Ton): Load is connected to Vs; FD reverse biased. Current rises exponentially from I1 to I2:

Vs = R·i + L·di/dt + E
i = I1·e^(−t/τ) + ((Vs − E)/R)(1 − e^(−t/τ)),  τ = L/R

Mode 2 – CH OFF (0 < t < Toff): Inductor energy keeps current flowing through FD; vo = 0. Current decays from I2 to I1:

0 = R·i + L·di/dt + E
i = I2·e^(−t/τ) − (E/R)(1 − e^(−t/τ))

Waveforms (continuous current):

vo Vs |‾‾‾‾|____|‾‾‾‾|____
      0   Ton   T
io I2 |   /\     /\
   I1 |__/  \___/  \___
      (rises: CH)(falls: FD)

Output relations:

Vo = (1/T)∫₀^(Ton) Vs dt = k·Vs
Io = (k·Vs − E)/R
ΔI = I2 − I1, maximum at k = 0.5:
ΔImax = (Vs/R)·tanh(R/(4fL)) ≈ Vs/(4fL)

Higher chopping frequency or larger L gives smoother current. Used for DC motor speed control.

✓ Answer checked by Claude Opus 5.5 (high effort)

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