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Linear fractional map -2, 0, 2 to ∞, 1/2, 3/4

Short answer

Let w=(az+b)/(cz+d). The conditions give d=2c, c=b, and a=1 with b=c=1, so w=(z+1)/(z+2).

Find linear fractional transformation mapping of: -2 ↦ ∞, 0 ↦ 1/2, 2 ↦ 3/4.

Find w = (az + b)/(cz + d) with −2 → ∞, 0 → 1/2, 2 → 3/4.

Conditions

  • z = −2 maps to ∞: the denominator vanishes, −2c + d = 0, so d = 2c.
  • z = 0 maps to 1/2: b/d = 1/2, so d = 2b. Hence 2c = 2b and c = b.
  • z = 2 maps to 3/4: (2a + b)/(2c + d) = 3/4.

Take b = c = 1. Then d = 2. The third condition gives (2a + 1)/(2 + 2) = 3/4, so 2a + 1 = 3 and a = 1.

Answer: w = (z + 1)/(z + 2)

Check

  • z = −2: denominator 0, so w = ∞ ✓
  • z = 0: 1/2 ✓
  • z = 2: 3/4 ✓

Also ad − bc = 2 − 1 = 1 ≠ 0, so the transformation is non-degenerate.

✓ Answer checked by Claude Opus 5.5 (high effort)

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