- Practice · 6 marks
Surface of revolution: equation, points, area
Short answer
Rotating the line from (2,0,0) to (4,0,6) about the Z-axis yields P(s,phi)=((2+2s)cos phi, (2+2s)sin phi, 6s). Points: (0,3,3); (-4,0,6); (1.768,1.768,1.5). Area = pi(2+4)*sqrt(40) = 119.2 square units.
Describe the surface of revolution. A straight line from (2, 0, 0) to (4, 0, 6) in the XZ plane is revolved about the Z axis. Write the parametric equation of the surface, find the points for (s, phi) = (0.5, 90 deg), (1, 180 deg) and (0.25, 45 deg), and calculate the curved surface area.
A surface of revolution is formed by rotating a plane curve (the generatrix or profile) about an axis in its plane. Every point of the curve moves on a circle (parallel); each position of the curve is a meridian. For a profile , about the Z axis:
Generatrix
The line is , for .
The surface is the side of a frustum of a cone with bottom radius 2, top radius 4 and height 6.
Points
| 0.5 | 90 deg | 3 | (0, 3, 3) |
| 1 | 180 deg | 4 | (-4, 0, 6) |
| 0.25 | 45 deg | 2.5 | (1.768, 1.768, 1.5) |
Curved surface area
Slant length .
Answer: P(s, phi) = ((2+2s)cos phi, (2+2s)sin phi, 6s); points (0,3,3), (-4,0,6), (1.768,1.768,1.5); area = 119.2 square units.
✓ Answer checked by Claude Opus 5.5 (high effort)
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