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Define Big O, Omega and Theta
Short answer
Big O: f(n) ≤ c·g(n) for n ≥ n₀ (upper bound). Big Omega: f(n) ≥ c·g(n) for n ≥ n₀ (lower bound). Big Theta: c₁·g(n) ≤ f(n) ≤ c₂·g(n) for n ≥ n₀ (tight bound). Example: 3n+2 = Θ(n).
Define Big O, Big Omega and Big Theta notation (with their respective curves).
Big O notation (upper bound)
f(n) = O(g(n)) if there exist positive constants c and n₀ such that f(n) ≤ c·g(n) for all n ≥ n₀. It states that f grows no faster than g (worst case guarantee).
time
| c*g(n)
| /
| / . f(n)
| / .
| /.
|______/._____________ n
n0
Example: 3n + 2 ≤ 4n for n ≥ 2, so 3n + 2 = O(n).
Big Omega notation (lower bound)
f(n) = Ω(g(n)) if there exist positive constants c and n₀ such that f(n) ≥ c·g(n) for all n ≥ n₀. It states that f grows at least as fast as g.
time
| f(n)
| .
| . ___ c*g(n)
| . ___/
| .___/
|_/__________________ n
n0
Example: 3n + 2 ≥ 3n for n ≥ 1, so 3n + 2 = Ω(n).
Big Theta notation (tight bound)
f(n) = Θ(g(n)) if there exist positive constants c₁, c₂ and n₀ such that c₁·g(n) ≤ f(n) ≤ c₂·g(n) for all n ≥ n₀. Equivalent to f = O(g) and f = Ω(g).
time
| c2*g(n)
| /
| / f(n)
| / . '
| / .' c1*g(n)
| /.' ____--
|_/'--________________ n
n0
Example: 3n ≤ 3n + 2 ≤ 4n for n ≥ 2, so 3n + 2 = Θ(n).
✓ Answer checked by Claude Opus 5.5 (high effort)
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