- 2074 Bhadra · 3 marks
Linear homogeneous and non-homogeneous recurrence
Short answer
Linear homogeneous: a_n = c1 a_{n-1} + ... + ck a_{n-k}, no extra term. Example: a_n = 5a_{n-1} - 6a_{n-2}. Non-homogeneous: includes a function F(n) ≠ 0. Example: a_n = 2a_{n-1} + 3^n. Solution is homogeneous solution plus particular solution.
State linear homogeneous and non-homogeneous recurrence relation with examples.
A linear recurrence relation with constant coefficients of order k has the form
aₙ = c₁aₙ₋₁ + c₂aₙ₋₂ + ... + cₖaₙ₋ₖ + F(n),
where c₁, ..., cₖ are real constants and cₖ ≠ 0.
- Linear homogeneous: F(n) = 0, so every term is a multiple of an earlier term. Examples: aₙ = 5aₙ₋₁ − 6aₙ₋₂; Fibonacci fₙ = fₙ₋₁ + fₙ₋₂. Solved with the characteristic equation rᵏ − c₁rᵏ⁻¹ − ... − cₖ = 0.
- Linear non-homogeneous: F(n) ≠ 0 is a function of n only. Examples: aₙ = 2aₙ₋₁ + 3ⁿ; aₙ = aₙ₋₁ + n (F(n) = n); Hanoi: Hₙ = 2Hₙ₋₁ + 1. The solution is aₙ = aₙ⁽ʰ⁾ + aₙ⁽ᵖ⁾, a homogeneous solution plus any particular solution.
| Relation | Type | Reason |
|---|---|---|
| aₙ = 3aₙ₋₁ | linear homogeneous, order 1 | no extra term |
| aₙ = 2aₙ₋₁ + 2n² | linear non-homogeneous | F(n) = 2n² |
| aₙ = aₙ₋₁² + aₙ₋₂ | not linear | aₙ₋₁ squared |
| aₙ = n·aₙ₋₁ | linear homogeneous but not constant coefficients | multiplier n |
✓ Answer checked by Claude Opus 5.5 (high effort)
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