- 2070 Bhadra · 4 marks
Truth value of a compound formula (b)
Short answer
((P∧¬Q)↔(Q∧R)) is true (F↔F), and (S∨¬Q) is true, so the implication is true. Truth value: TRUE.
If P = F, Q = T, S = T, R = F, then find truth value of: ((P ∧ ¬Q) ↔ (Q ∧ R)) → (S ∨ ¬Q)
Given P = F, Q = T, S = T, R = F. Formula: ((P ∧ ¬Q) ↔ (Q ∧ R)) → (S ∨ ¬Q)
| Step | Sub-formula | Working | Value |
|---|---|---|---|
| 1 | ¬Q | ¬T | F |
| 2 | P ∧ ¬Q | F ∧ F | F |
| 3 | Q ∧ R | T ∧ F | F |
| 4 | (P ∧ ¬Q) ↔ (Q ∧ R) | F ↔ F | T |
| 5 | S ∨ ¬Q | T ∨ F | T |
| 6 | whole: step 4 → step 5 | T → T | T |
Answer: the truth value is TRUE.
✓ Answer checked by Claude Opus 5.5 (high effort)
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