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Truth value of a compound formula (b)

Short answer

((P∧¬Q)↔(Q∧R)) is true (F↔F), and (S∨¬Q) is true, so the implication is true. Truth value: TRUE.

If P = F, Q = T, S = T, R = F, then find truth value of: ((P ∧ ¬Q) ↔ (Q ∧ R)) → (S ∨ ¬Q)

Given P = F, Q = T, S = T, R = F. Formula: ((P ∧ ¬Q) ↔ (Q ∧ R)) → (S ∨ ¬Q)

StepSub-formulaWorkingValue
1¬Q¬TF
2P ∧ ¬QF ∧ FF
3Q ∧ RT ∧ FF
4(P ∧ ¬Q) ↔ (Q ∧ R)F ↔ FT
5S ∨ ¬QT ∨ FT
6whole: step 4 → step 5T → TT

Answer: the truth value is TRUE.

✓ Answer checked by Claude Opus 5.5 (high effort)

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