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No-load and blocked rotor tests of induction motor

Short answer

No-load test runs motor at rated voltage unloaded, measuring Po, Io, Vo to find core-loss resistance Rc and magnetizing reactance Xm after subtracting copper losses. Blocked-rotor test applies reduced voltage to pass rated current with rotor stalled, giving total leakage impedance Zeq=R1+R2' and Xeq=X1+X2'; R1 from DC test. These form the per-phase equivalent circuit.

Explain the no-load test and blocked rotor test of a three-phase induction motor. How the data obtained from these tests can be used to calculate the equivalent circuit parameters of the motor?

The no-load test and the blocked rotor test of a three-phase induction motor are the counterparts of the open-circuit and short-circuit tests of a transformer. Together they give the parameters of the per-phase equivalent circuit (R1,X1,R2′,X2′,Rc,XmR_1, X_1, R_2', X_2', R_c, X_m) without loading the motor.

Circuit used

 3-ph       +--[A]--[W1]--+
 variable --|             |--- 3-ph
 supply  ---+--[ ]--[W2]--+--- induction
 (autotr.)  |     [V]     |--- motor
            +-------------+
 Two-wattmeter method: P = W1 + W2

An ammeter, a voltmeter and two wattmeters (two-wattmeter method) are connected between a variable three-phase supply (autotransformer) and the stator.

No-load test

Procedure: The motor runs uncoupled from any load at rated voltage and rated frequency. Readings: line voltage V0V_0, line current I0I_0 and input power P0=W1+W2P_0 = W_1 + W_2.

Theory: At no load the slip is very small (s≈0s \approx 0), so R2′/sR_2'/s is very large and the rotor branch is practically open. The current I0I_0 (25–40 % of rated, because of the air gap) is mainly magnetising current. Input power covers:

P0=stator Cu loss+core loss+friction and windage lossP_0 = \text{stator Cu loss} + \text{core loss} + \text{friction and windage loss}

Calculations (per phase, star equivalent):

Vph=V03,cos⁡ϕ0=P03 V0I0Prot=P0−3I02R1(core + mechanical loss)Iw=I0cos⁡ϕ0,Iμ=I0sin⁡ϕ0Rc=VphIw,Xm=VphIμ\begin{aligned} V_{ph} &= \frac{V_0}{\sqrt{3}}, \qquad \cos\phi_0 = \frac{P_0}{\sqrt{3}\,V_0 I_0} \\ P_{rot} &= P_0 - 3 I_0^2 R_1 \quad (\text{core + mechanical loss}) \\ I_w &= I_0 \cos\phi_0, \qquad I_\mu = I_0 \sin\phi_0 \\ R_c &= \frac{V_{ph}}{I_w}, \qquad X_m = \frac{V_{ph}}{I_\mu} \end{aligned}

Also Z0=Vph/I0≈X1+XmZ_0 = V_{ph}/I_0 \approx X_1 + X_m, so a more accurate value is Xm=X0−X1X_m = X_0 - X_1 once X1X_1 is known from the blocked rotor test. Friction and windage loss can be separated from core loss by repeating the test at reduced voltages and extrapolating the P0P_0–V2V^2 curve to zero voltage.

Blocked rotor test

Procedure: The rotor is held stationary (blocked) and a reduced voltage (about 10–20 % of rated) is applied, raised until rated current flows. Readings: VscV_{sc}, IscI_{sc}, PscP_{sc}. For accurate rotor values, the test is ideally done at about 25 % of rated frequency, since the rotor normally works at slip frequency.

Theory: With the rotor at rest, s=1s = 1, so R2′/s=R2′R_2'/s = R_2' is small. The magnetising branch has a much higher impedance and, at low voltage, draws very little current; it is neglected. Core loss is negligible at low voltage and there is no mechanical loss, so PscP_{sc} is almost entirely the full-load copper loss of stator and rotor.

Calculations (per phase):

Zeq=Vsc/3Isc,Req=Psc3Isc2=R1+R2′Xeq=Zeq2−Req2=X1+X2′R2′=Req−R1\begin{aligned} Z_{eq} &= \frac{V_{sc}/\sqrt{3}}{I_{sc}}, \qquad R_{eq} = \frac{P_{sc}}{3 I_{sc}^2} = R_1 + R_2' \\ X_{eq} &= \sqrt{Z_{eq}^2 - R_{eq}^2} = X_1 + X_2' \\ R_2' &= R_{eq} - R_1 \end{aligned}

R1R_1 is measured by a DC test on the stator winding (DC resistance multiplied by about 1.2 for skin effect; for a star winding, R1=Rdc, line/2R_1 = R_{dc,\,line}/2).

Splitting XeqX_{eq}: Usually X1=X2′=Xeq/2X_1 = X_2' = X_{eq}/2 (IEEE gives other ratios, e.g. 0.4 : 0.6 for class B and 0.3 : 0.7 for class C designs).

Using the results: equivalent circuit

  R1    jX1          jX2'     R2'
 -^^^---mmm----+------mmm------^^^--+
               |    |               |
 V1          Rc[]  []jXm            [] R2'(1-s)/s
               |    |               |    (load)
 --------------+------+-------------+
ParameterObtained from
R1R_1DC resistance test
R2′R_2'Blocked rotor test minus R1R_1
X1, X2′X_1,\ X_2'Blocked rotor test (XeqX_{eq} split)
RcR_cNo-load test (IwI_w)
XmX_mNo-load test (IμI_\mu)
Rotational lossNo-load test

With these values the equivalent circuit can predict current, power factor, torque, efficiency and slip at any load, and the data can also be used to draw the circle diagram.

✓ Answer checked by Claude Opus 5.5 (high effort)

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