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Dynamic equation of GVF, wide rectangular form
Short answer
From dH/dx = -Sf and dH = dz + dy + d(V²/2g), derive dy/dx = (S₀ - Sf)/(1 - Fr²). For a wide rectangle, using Manning’s equation, Sf/S₀ = (yₙ/y)^(10/3) and Fr² = (yc/y)³, giving dy/dx = S₀[1 - (yₙ/y)^(10/3)] / [1 - (yc/y)³].
Derive the dynamic equation of Gradually Varied Flow (GVF) and convert the derived equation for the case of wide rectangular channel, using Manning's equation, into following form: where = bed slope, = normal depth, = critical depth.
Dynamic equation of GVF
Assumptions: steady flow; hydrostatic pressure distribution (small slope); the channel is prismatic; the energy loss is given by the uniform-flow formula using the local depth and velocity; .
Take a short reach of an open channel. The total head above a datum is
where is the bed level, the depth and . The bed slope is and the energy slope is . Differentiating with respect to :
Since :
Therefore
Physical meaning: the numerator is the difference between the bed slope and the slope of the energy line. If , depth tends to increase in the flow direction (for subcritical flow); the denominator decides the sign by flow regime ( subcritical, supercritical). When , and (uniform flow). When , and (the surface meets the critical depth line steeply).
Wide rectangular form using Manning's equation
For a wide rectangular channel, , and .
Friction slope from Manning's equation :
At normal depth and :
Froude number: at critical depth , so
Substituting into the dynamic equation:
✓ Answer checked by Claude Opus 5.5 (high effort)
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