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Hump and constriction: critical depth, 1.8 m channel

Short answer

Critical depth does not occur for the hump alone (available energy 0.913 m > E_c 0.752 m) nor for the sidewall contraction alone (1.063 m > 0.934 m). With both together, E_c + Δz = 1.084 m > approach energy 1.063 m, so flow chokes: critical depth 0.623 m occurs and upstream depth rises to 1.024 m.

A flow of 2 m³/s is carried in a rectangular channel 1.8 m wide at a depth of 1.0 m. Will critical depth occur at a section where (a) a frictionless hump 15 cm high is installed across the bed? (b) a frictionless sidewall reduces the channel width to 1.3 m? (c) the hump and the sidewall constriction are installed together?

Given: Q=2 m3/sQ = 2\ \text{m}^3/\text{s}, B=1.8 mB = 1.8\ \text{m}, y1=1.0 my_1 = 1.0\ \text{m}. The approach flow is subcritical.

Approach specific energy

q1=21.8=1.111 m2/s,V1=1.111 m/sE1=1.0+1.11122×9.81=1.063 m\begin{aligned} q_1 &= \frac{2}{1.8} = 1.111\ \text{m}^2/\text{s},\quad V_1 = 1.111\ \text{m/s} \\ E_1 &= 1.0 + \frac{1.111^2}{2 \times 9.81} = 1.063\ \text{m} \end{aligned}

Rule: critical depth occurs at the section only if the energy available there is not more than the minimum energy needed, E1−Δz≤Ec=1.5 ycE_1 - \Delta z \le E_c = 1.5\,y_c (with yc=(q2/g)1/3y_c = (q^2/g)^{1/3}).

(a) Hump of 0.15 m

yc=(1.11129.81)1/3=0.501 m,Ec=0.752 my_c = \left(\frac{1.111^2}{9.81}\right)^{1/3} = 0.501\ \text{m},\quad E_c = 0.752\ \text{m}

Available energy over the hump =1.063−0.15=0.913 m>0.752 m= 1.063 - 0.15 = 0.913\ \text{m} > 0.752\ \text{m}.

No critical depth. The flow stays subcritical over the hump with y≈0.82 my \approx 0.82\ \text{m}.

(b) Side-wall contraction to 1.3 m

q2=21.3=1.538 m2/s,yc=(1.53829.81)1/3=0.623 m,Ec=0.934 mq_2 = \frac{2}{1.3} = 1.538\ \text{m}^2/\text{s},\quad y_c = \left(\frac{1.538^2}{9.81}\right)^{1/3} = 0.623\ \text{m},\quad E_c = 0.934\ \text{m}

Available energy =1.063 m>0.934 m= 1.063\ \text{m} > 0.934\ \text{m}.

No critical depth. The depth in the throat is about 0.92 m (subcritical).

(c) Hump and contraction together

Ec+Δz=0.934+0.15=1.084 m>E1=1.063 mE_c + \Delta z = 0.934 + 0.15 = 1.084\ \text{m} > E_1 = 1.063\ \text{m}

The approach flow does not have enough energy. Critical depth does occur at the throat (y=yc=0.623 my = y_c = 0.623\ \text{m}) and the flow chokes. The upstream depth rises until E1′=1.084 mE_1' = 1.084\ \text{m}:

y1′+1.11122g y1′2=1.084⇒y1′=1.024 my_1' + \frac{1.111^2}{2 g\, y_1'^2} = 1.084 \Rightarrow y_1' = 1.024\ \text{m}

Answer: (a) No, (b) No, (c) Yes. In (c) the upstream depth is raised from 1.00 m to about 1.02 m.

✓ Answer checked by Claude Opus 5.5 (high effort)

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