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Shield's diagram and its application

Short answer

Shields' diagram relates dimensionless critical shear stress τ* = τc/((γs−γ)d) to boundary Reynolds number Re* = u*d/ν. For Re* > 400 (fully rough) τ* ≈ 0.056; a minimum of about 0.03 occurs near Re* ≈ 10. Design iterates: assume τ*, compute τc and Re*, refine τ* from the diagram, then check that actual bed shear γRS0 ≤ τc.

Explain Shield's diagram (with sketch, including the important points based on critical Reynolds number) and its application in designing / predicting critical tractive force for a mobile boundary channel.

Shields diagram

Shields (1936) showed by experiments that the start of motion of non-cohesive sediment depends on two dimensionless numbers:

  • Shields parameter (dimensionless critical shear stress): τ∗=τc(γs−γ) d\tau_* = \dfrac{\tau_c}{(\gamma_s - \gamma)\,d}
  • Boundary (shear) Reynolds number: Re∗=u∗ dνRe_* = \dfrac{u_*\,d}{\nu}, with u∗=τ0/ρu_* = \sqrt{\tau_0/\rho} the shear velocity

where τc\tau_c is the critical bed shear stress, γs\gamma_s and γ\gamma the specific weights of sediment and water, dd the grain size and ν\nu the kinematic viscosity.

 tau*
 0.1 |\
     | \
     |  \                     ___________  0.056
 0.05|   '.                _.-'
     |     '.          _.-'
 0.03|       '-..__..-'      <- minimum
     |    (smooth)  (transition) (rough)
     +------+--------+---------+------------> Re*
           2        10        400
  above curve: bed moves ; below curve: no motion

Important points (based on Re∗Re_*):

Range of Re∗Re_*Boundary typeBehaviour of τ∗\tau_*
Re∗<2Re_* < 2 (about)hydraulically smooth; grains lie inside the viscous sublayerτ∗\tau_* falls as Re∗Re_* rises (about 0.1 at Re∗≈1Re_* \approx 1)
2<Re∗<4002 < Re_* < 400transitionτ∗\tau_* passes through a minimum of about 0.03 near Re∗≈10Re_* \approx 10 and rises again
Re∗>400Re_* > 400fully rough turbulentτ∗\tau_* becomes constant, about 0.056 (taken as 0.06), independent of Re∗Re_*

The curve separates the region of no motion (below) from the region of sediment motion (above).

Application in design

To find the critical shear stress for a given grain size dd:

  1. Assume τ∗\tau_* (for coarse material 0.056 to 0.06).
  2. Find τc=τ∗(γs−γ)d\tau_c = \tau_*(\gamma_s - \gamma)d and u∗=τc/ρu_* = \sqrt{\tau_c/\rho}.
  3. Compute Re∗=u∗d/νRe_* = u_*d/\nu, read the correct τ∗\tau_* from the diagram and repeat until it agrees.

To check or design a channel:

  1. Compute the actual bed shear stress τ0=γRS0\tau_0 = \gamma R S_0 (or γyS0\gamma y S_0).
  2. If τ0<τc\tau_0 < \tau_c the bed is stable; if τ0>τc\tau_0 > \tau_c the bed material moves.
  3. For design, choose the bed material (or a stable size dd) so that τc≥τ0\tau_c \ge \tau_0. For fully rough flow, the size that just stays stable is dcr≈10 RS0d_{cr} \approx 10\,R S_0 (with γs=2.65γ\gamma_s = 2.65\gamma).

✓ Answer checked by Claude Opus 5.5 (high effort)

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