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Characteristics and response of zero-order system

Short answer

A zero-order system output is proportional to input instantly, with no lag or phase shift; amplitude ratio = 1, phase = 0 at all frequencies. A linear potentiometer gives e_o ∝ x with K = E/L, behaving as zero-order only when input changes are slow compared to its natural frequency, as real pots have mass, inductance and loading effects that introduce higher-order dynamics.

Explain the characteristics and response of a zero-order measurement system. Why is a linear potentiometer considered a zero-order instrument, and what are the limits of this assumption?

A zero-order system has the model a0qo=b0qia_0 q_o = b_0 q_i, so qo=Kqiq_o = K q_i with static sensitivity K=b0/a0K = b_0/a_0.

Characteristics

  • The output is proportional to the input at every instant. There is no lag, delay, phase shift or distortion.
  • Amplitude ratio M=1M = 1 (relative to KK) and phase angle ϕ=0\phi = 0 at all frequencies.
  • The only parameter is KK, found by static calibration.
  • No energy storage (no mass, spring or capacitance) in the model.

Response

For any input, a step, ramp or sine, the output has the same shape scaled by KK.

 q_i |  ____        q_o |  ____   (scaled by K)
     | |    |           | |    |
     +-+----+--> t      +-+----+--> t

Potentiometer as example

A linear potentiometer of length LL and supply EE gives eo=(E/L) xe_o = (E/L)\,x, so K=E/LK = E/L V/m. The output follows the wiper position with no dynamic lag.

Limits

A zero-order model is an idealization valid only when the input changes slowly compared with the instrument's natural frequency. In a real potentiometer, wiper mass and inertia, wire-wound resolution, friction, stray capacitance and inductance, and the loading error of a finite load give time-dependent behaviour at high frequency, so the true response is of higher order.

✓ Answer checked by Claude Opus 5.5 (high effort)

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