- 2069 Bhadra · 4 marks
Forward difference table
Short answer
The forward difference table first row is 2, 7, 12, 6, 0, 0. The third differences are constant 6 and fourth differences are zero, indicating f(x) is a cubic polynomial x³+1.
Generate forward difference table from the following data.
| x | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| f(x) | 2 | 9 | 28 | 65 | 126 | 217 |
Here h = 1. A forward difference table lists Δyᵢ = yᵢ₊₁ − yᵢ, then Δ²yᵢ = Δyᵢ₊₁ − Δyᵢ, and so on, until the differences vanish.
| x | y | Δy | Δ²y | Δ³y | Δ⁴y | Δ⁵y |
|---|---|---|---|---|---|---|
| 1 | 2 | 7 | 12 | 6 | 0 | 0 |
| 2 | 9 | 19 | 18 | 6 | 0 | |
| 3 | 28 | 37 | 24 | 6 | ||
| 4 | 65 | 61 | 30 | |||
| 5 | 126 | 91 | ||||
| 6 | 217 |
Working:
Δf: 9−2 = 7, 28−9 = 19, 65−28 = 37, 126−65 = 61, 217−126 = 91
Δ²f: 19−7 = 12, 37−19 = 18, 61−37 = 24, 91−61 = 30
Δ³f: 18−12 = 6, 24−18 = 6, 30−24 = 6
Δ⁴f: 0, 0, ...
The third differences are constant (= 6) and the fourth differences are zero, so f(x) is a cubic polynomial (indeed f(x) = x³ + 1). The first row (2, 7, 12, 6, 0, 0) is the set of values used by Newton's forward formula.
✓ Answer checked by Claude Opus 5.5 (high effort)
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