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Aliasing; Nyquist of 6cos50πt + …

Short answer

Aliasing distorts a sampled signal when f_s < 2f_max, making high frequencies appear as lower ones. It is overcome with an anti-aliasing low-pass filter before sampling and sampling at f_s > 2f_max. For x(t)=6cos50πt+20sin300πt−10cos100πt, frequencies are 25, 150, 50 Hz; f_max=150 Hz. Nyquist rate = 300 Hz; sampling must be >300 Hz to avoid zeroing the sine term.

What is aliasing effect and how can we overcome it? Determine the Nyquist rate for a continuous time signal x(t) = 6cos50πt + 20sin300πt − 10cos100πt.

Aliasing effect

Aliasing is the distortion that occurs when a signal is sampled at a rate lower than its Nyquist rate (fs<2fMf_s < 2f_M). The shifted copies of the spectrum in the sampled signal overlap, so a high-frequency component "folds back" and appears as a lower frequency (its alias). After overlap the original spectrum cannot be separated by any filter, so the signal cannot be recovered exactly.

Example: a 700 Hz tone sampled at fs=1000f_s = 1000 Hz gives the same samples as a 1000−700=3001000-700 = 300 Hz tone.

How to overcome aliasing:

  1. Sample fast enough: choose fs>2fMf_s > 2f_M (in practice fsf_s is kept 2.5 to 5 times fMf_M to leave a guard band).
  2. Anti-aliasing filter: pass the signal through an analog low-pass filter with cutoff fs/2f_s/2 before sampling, so that no component above fs/2f_s/2 reaches the sampler. Real signals and noise are never strictly band-limited, so this filter is always used in practice.
  3. Oversampling: sample at a much higher rate, then low-pass filter and decimate digitally. This relaxes the sharpness needed in the analog anti-aliasing filter.

Nyquist rate of x(t)=6cos⁡50πt+20sin⁡300πt−10cos⁡100πtx(t) = 6\cos 50\pi t + 20\sin 300\pi t - 10\cos 100\pi t

Termω\omega (rad/s)ff (Hz)
6cos⁡50πt6\cos 50\pi t50π50\pi2525
20sin⁡300πt20\sin 300\pi t300π300\pi150150
−10cos⁡100πt-10\cos 100\pi t100π100\pi5050

fM=150f_M = 150 Hz.

fN=2fM=2×150=300 Hzf_N = 2 f_M = 2\times150 = 300\ \text{Hz}

Answer: Nyquist rate = 300 Hz (300 samples/s, ωN=600π\omega_N = 600\pi rad/s). (Sampling at exactly 300 Hz would make every sample of sin⁡300πt\sin 300\pi t zero, so in practice fsf_s must be strictly greater than 300 Hz.)

✓ Answer checked by Claude Opus 5.5 (high effort)

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