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CTFT convolution property
Short answer
Convolution in time corresponds to multiplication in frequency: x(t)*h(t) ↔ X(ω)H(ω). The proof substitutes the convolution integral into the Fourier definition, interchanges integration order, uses the time-shift property to obtain e^{-jωτ}H(ω), and integrates over τ to yield X(ω)H(ω).
State and prove the convolution property of the continuous time Fourier transform (show that convolution in time domain results in multiplication in frequency domain).
Statement
If and , then
Convolution in the time domain becomes multiplication in the frequency domain.
Proof
By the definition :
Change the order of integration:
In the inner integral put (, limits unchanged):
This is the time-shift property. Substituting back:
Significance
- LTI analysis: the output of an LTI system with impulse response is . is the frequency response: each frequency component of the input is scaled by and phase-shifted by .
- Filtering: an ideal low-pass filter has for and 0 elsewhere. It removes the high-frequency parts of simply by multiplication.
- Cascades: systems in series give .
- Computation: a convolution integral can be replaced by: transform, multiply, inverse transform.
Example
is applied to , with and both positive:
So , found without evaluating the convolution integral.
Dual (multiplication/modulation) property: .
✓ Answer checked by Claude Opus 5.5 (high effort)
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