Skip to main content

Energy vs power spectral density

Short answer

Energy spectral density Ψ(ω)=|X(jω)|^2 applies to energy signals; total energy E=(1/2π)∫Ψ dω, unit J/Hz. Power spectral density S(ω)=lim_{T→∞}|X_T(jω)|^2/T applies to power signals; total power P=(1/2π)∫S dω, unit W/Hz. Both are real, non‑negative and even for real signals.

Differentiate between energy and power spectral density.

Energy spectral density (ESD) shows how the energy of an energy signal is distributed over frequency, while power spectral density (PSD) shows how the average power of a power signal is distributed over frequency.

PointEnergy spectral densityPower spectral density
Used forEnergy signals (0<E<∞0 < E < \infty, P=0P = 0)Power signals (0<P<∞0 < P < \infty, E=∞E = \infty)
DefinitionΨ(ω)=∣X(jω)∣2\Psi(\omega) = \lvert X(j\omega)\rvert^2S(ω)=lim⁡T→∞∣XT(jω)∣2TS(\omega) = \lim_{T\to\infty}\frac{\lvert X_T(j\omega)\rvert^2}{T}
Total quantityE=12π∫Ψ(ω)dωE = \frac{1}{2\pi}\int \Psi(\omega)d\omegaP=12π∫S(ω)dωP = \frac{1}{2\pi}\int S(\omega)d\omega
UnitJ/HzW/Hz
FT pair withEnergy autocorrelation R(τ)=∫x(t)x(t+τ)dtR(\tau)=\int x(t)x(t+\tau)dtPower autocorrelation R(τ)=lim⁡1T∫−T/2T/2x(t)x(t+τ)dtR(\tau)=\lim\frac{1}{T}\int_{-T/2}^{T/2} x(t)x(t+\tau)dt
Typical signalsPulses, decaying exponentialsPeriodic signals, DC, random noise
Periodic signal caseNot definedImpulses: 2π∑∣ak∣2δ(ω−kω0)2\pi\sum \lvert a_k\rvert^2\delta(\omega-k\omega_0)

Both are real, non-negative and even in ω\omega for real signals, and both lose phase information.

Example: x(t)=e−tu(t)x(t) = e^{-t}u(t) is an energy signal with ESD 11+ω2\frac{1}{1+\omega^2}; x(t)=cos⁡ω0tx(t) = \cos\omega_0 t is a power signal with PSD π2[δ(ω−ω0)+δ(ω+ω0)]\frac{\pi}{2}[\delta(\omega-\omega_0)+\delta(\omega+\omega_0)].

✓ Answer checked by Claude Opus 5.5 (high effort)

All Signals and Systems chapter 3 questions →