- 2078 Baisakh · 2+6 marks
Impulse train sampling and reconstruction
Short answer
Impulse train sampling multiplies the signal by a periodic impulse train, producing impulse-weighted samples. Reconstruction passes these samples through an ideal low-pass filter with gain T and cutoff between ω_m and ω_s−ω_m, provided ω_s > 2ω_m; in time domain this corresponds to sinc interpolation of the sample values.
What is impulse train sampling? How do you reconstruct original signal from its sample?
Impulse train sampling
Impulse train (ideal) sampling multiplies the continuous signal by a periodic train of unit impulses spaced seconds apart. The result is a train of impulses whose strengths are the sample values:
is the sampling period and the sampling frequency.
Spectrum of the sampled signal
. Multiplication in time is convolution in frequency:
So is repeated at every multiple of , scaled by .
X(jw) Xp(jw), ws > 2wm
/\ /\ /\ /\
/ \ / \ / \ / \
-+-+--+--> w --+--+--+-+--+--+-+--+--> w
-wm 0 wm -ws 0 wm ws
Reconstruction from samples
- Condition: must be band-limited to , and (Nyquist). Then the copies do not overlap.
- Ideal low-pass filter: pass through an LPF with gain and cutoff , where (usually ):
- Time-domain view (interpolation): the filter's impulse response is . Convolving it with the impulse train gives
With this becomes : each sample is replaced by a sinc pulse, and the sum of these pulses fills in the values between samples exactly.
x(t) --(x)--> xp(t) --> [ LPF: gain T, cutoff wc ] --> xr(t) = x(t)
^
p(t) = sum delta(t - nT)
Practical note: an ideal LPF is non-causal, so real systems use a zero-order hold (D/A converter) followed by a smoothing filter, and sample a little above the Nyquist rate to leave a guard band.
✓ Answer checked by Claude Opus 5.5 (high effort)
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