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Quick sand condition

Short answer

Quick sand condition occurs when upward seepage makes effective stress zero in cohesionless soil, so it loses shear strength and behaves like a liquid. The critical hydraulic gradient is ic = gamma'/gamma_w = (G-1)/(1+e), about 1 for typical sands.

What is the quick sand condition? Explain the quick sand condition (during upward seepage flow).

Quick sand condition is the state in which the effective stress of a cohesionless soil becomes zero because of upward seepage of water. The soil then has no shear strength and behaves like a liquid. It is not a type of sand; any cohesionless soil (sand, silt) can become "quick".

Explanation (upward flow)

Consider a soil layer of thickness LL with water flowing upward under a head difference hh.

   h  ↑  water level in standpipe
  ----+----------------
      |   water
  ----+----------------  top of soil
      |   sand  L
  ----+----------------  base of soil
        ↑ ↑ ↑ upward flow

At the base of the soil layer:

  • Total stress σ=γsatL\sigma = \gamma_{sat} L
  • Pore pressure u=γw(L+h)u = \gamma_w (L + h) (excess head hh added)
  • Effective stress σ′=γsatL−γw(L+h)=γ′L−γwh\sigma' = \gamma_{sat}L - \gamma_w(L+h) = \gamma' L - \gamma_w h

As hh increases, σ′\sigma' falls. When σ′=0\sigma' = 0:

γ′L=γwh⇒ic=hL=γ′γw=G−11+e\gamma' L = \gamma_w h \quad \Rightarrow \quad i_c = \frac{h}{L} = \frac{\gamma'}{\gamma_w} = \frac{G-1}{1+e}

At this critical hydraulic gradient the seepage force just balances the submerged weight of the soil. The sand particles lose contact, boil up and the soil loses bearing capacity. For most sands ic≈1i_c \approx 1.

Quick condition often causes failure of excavations, cofferdams and the downstream toe of hydraulic structures (piping).

✓ Answer checked by Claude Opus 5.5 (high effort)

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