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Road compaction specification, sand cone

Short answer

Sand cone volumes are 21.24 and 17.41 cm3 for locations 1 and 2. Location 1 has RC 92.8% and w 14.0%, location 2 has RC 94.9% and w 16.05%; specification requires RC at least 95% and w 11.5-15.5%, so neither location satisfies.

In the construction of a road, the compaction specification required was 95% of Proctor maximum dry density at a field moisture content within 2% of the optimum moisture content. The maximum dry density and optimum moisture content obtained in the laboratory from the Standard Proctor test were 1.95 Mg/m³ and 13.5% respectively. A site engineer conducted sand cone test at two locations and obtained the following results.

Location No.Mass of soil removed (gm), WetMass of soil removed (gm), DryMass of sand used (gm)
143.8638.4639.51
237.3832.2132.39

The density of sand used was 1.86 Mg/m³. Check whether the specification was satisfied or not.

Sand cone test: volume of the hole = mass of sand filling it / density of sand. Then the field density and water content follow. The specification requires both

  • γd≥0.95 γd,max=0.95×1.95=1.8525\gamma_d \ge 0.95\,\gamma_{d,max} = 0.95 \times 1.95 = 1.8525 Mg/m³
  • ww within 13.5±2%13.5 \pm 2\%, that is 11.5% to 15.5%

Location 1

V=39.511.86=21.24 cm3V = \frac{39.51}{1.86} = 21.24\ \text{cm}^3 γbulk=43.8621.24=2.065 Mg/m3,γd=38.4621.24=1.811 Mg/m3\gamma_{bulk} = \frac{43.86}{21.24} = 2.065\ \text{Mg/m}^3, \qquad \gamma_d = \frac{38.46}{21.24} = 1.811\ \text{Mg/m}^3 w=43.86−38.4638.46×100=14.0%w = \frac{43.86 - 38.46}{38.46} \times 100 = 14.0\% RC=1.8111.95×100=92.8%RC = \frac{1.811}{1.95} \times 100 = 92.8\%

Location 2

V=32.391.86=17.41 cm3V = \frac{32.39}{1.86} = 17.41\ \text{cm}^3 γbulk=37.3817.41=2.147 Mg/m3,γd=32.2117.41=1.850 Mg/m3\gamma_{bulk} = \frac{37.38}{17.41} = 2.147\ \text{Mg/m}^3, \qquad \gamma_d = \frac{32.21}{17.41} = 1.850\ \text{Mg/m}^3 w=37.38−32.2132.21×100=16.05%w = \frac{37.38 - 32.21}{32.21} \times 100 = 16.05\% RC=1.8501.95×100=94.9%RC = \frac{1.850}{1.95} \times 100 = 94.9\%

Comparison

Locationγd\gamma_d (Mg/m³)RC (%)Required RCw (%)Allowed w
11.81192.89514.011.5 to 15.5
21.85094.99516.0511.5 to 15.5

Answer: The specification is not satisfied. Location 1 fails on density (RC 92.8% < 95%) though its water content is acceptable. Location 2 is just below 95% (94.9%) and its water content (16.05%) is above the 15.5% limit. Both areas need re-rolling (and drying at location 2).

The masses are taken as grams, as given; the result depends only on their ratios.

✓ Answer checked by Claude Opus 5.5 (high effort)

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