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Define strain energy; relation for bending

Short answer

Strain energy is energy stored in an elastic body equal to work done by external forces, area under load-displacement curve. Complementary strain energy is area between curve and load axis. For linear systems both equal ½PΔ. Strain energy due to bending: dU = M²dx/(2EI), integrated over length gives U_b = ∫ M²/(2EI) dx.

Define strain energy and complementary strain energy. Also derive the relationship of strain energy due to bending.

Strain energy

Strain energy UU is the energy stored in an elastic body by the work done by external forces in deforming it. It equals the area under the load-displacement curve (up to the displacement):

U=∫0ΔP dΔU = \int_0^\Delta P\,d\Delta

For linear behaviour, U=12PΔU = \tfrac12 P\Delta.

Complementary strain energy

Complementary strain energy U∗U^* is the area between the load-displacement curve and the load axis:

U∗=∫0PΔ dPU^* = \int_0^P \Delta\,dP
 P |        /
   |  U*  /|
   |    /  |      U + U* = P*Delta
   |  /  U |
   +-------+---- Delta

For a linear structure, U∗=U=12PΔU^* = U = \tfrac12 P\Delta; for a non-linear one they differ. Castigliano's theorems use UU (first) and U∗U^* (second).

Strain energy due to bending

An element dxdx under moment MM rotates by dθ=M dxEId\theta = \dfrac{M\,dx}{EI}. The moment grows gradually, so

dU=12M dθ=M2 dx2EIdU = \tfrac12 M\,d\theta = \frac{M^2\,dx}{2EI} Ub=∫0LM22EI dxU_b = \int_0^L \frac{M^2}{2EI}\,dx

Using the stress method as a check: σ=MyI\sigma = \dfrac{My}{I}, dU=∫σ22EdA dx=M22EI2(∫y2dA)dx=M2dx2EIdU = \displaystyle\int\frac{\sigma^2}{2E}dA\,dx = \frac{M^2}{2EI^2}\Big(\int y^2dA\Big)dx = \frac{M^2dx}{2EI}.

Example: cantilever with end load PP: M=PxM = Px, so Ub=∫0LP2x22EIdx=P2L36EIU_b = \displaystyle\int_0^L \frac{P^2x^2}{2EI}dx = \frac{P^2L^3}{6EI}.

✓ Answer checked by Claude Opus 5.5 (high effort)

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