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Strain energy, gradual vs sudden load, shear

Short answer

Strain energy is stored elastic energy. Gradually applied load: stress = P/A, deflection = PL/AE, work = ½Pδ. Suddenly applied load: full P acts instantly, stress = 2P/A, deflection = 2PL/AE. Shear strain energy: Us = ∫ (α V^2/(2GA)) dx, α=1.2 for rectangle.

Define strain energy and explain with examples the difference between gradually and suddenly applied direct loads. Derive the expression for strain energy due to shear force in a beam in bending.

Strain energy is the energy stored in a deformed elastic body due to the work done by external loads in deforming it. It is recovered when the load is removed (within the elastic limit). For a direct load, U=σ22E×VolumeU = \dfrac{\sigma^2}{2E}\times\text{Volume}.

Gradually and suddenly applied direct loads

PointGradual loadSudden load
ApplicationLoad increases slowly from 0 to PPFull load PP acts at once, from zero deflection
Work done12Pδ\tfrac12 P\deltaPδP\delta (force is constant throughout)
Stressσ=P/A\sigma = P/Aσ=2P/A\sigma = 2P/A
Deflectionδ=PL/AE\delta = PL/AEδ=2PL/AE\delta = 2PL/AE
ExampleSlowly lifting a weight with a hoistA weight released suddenly on a collar from zero height

For sudden loading, the work done PδmaxP\delta_{max} equals the strain energy 12kδmax2\tfrac12 k\delta_{max}^2, so δmax=2P/k\delta_{max} = 2P/k: the stress and deflection are twice those for a gradually applied load.

Strain energy due to shear force in a beam

For an element of length dxdx with shear force VV, the shear stress at a distance yy from the neutral axis is τ=VA′yˉIb\tau = \dfrac{VA'\bar y}{Ib}, and the energy per unit volume is τ22G\dfrac{\tau^2}{2G}. Integrating over the area, for a rectangular section:

dU=∫τ22G dA dx,τ=V2I(d24−y2)dU = \int \frac{\tau^2}{2G}\,dA\,dx,\qquad \tau = \frac{V}{2I}\left(\frac{d^2}{4}-y^2\right) dU=V2b8GI2⋅d530 dx=65⋅V22GA dxdU = \frac{V^2 b}{8GI^2}\cdot\frac{d^5}{30}\,dx = \frac{6}{5}\cdot\frac{V^2}{2GA}\,dx

For any section:

Us=∫0LαV22GA dxU_s = \int_0^L \frac{\alpha V^2}{2GA}\,dx

where α\alpha is the shear form factor (α=1.2\alpha = 1.2 for a rectangle, 10/910/9 for a solid circle).

✓ Answer checked by Claude Opus 5.5 (high effort)

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