- 2068 Bhadra (old course) · 10 marks
Scale triangle Sx=3, Sy=2
Short answer
Multiply each vertex by scaling factors: x' = 3x, y' = 2y. A(18,18), B(30,10), C(12,6).
Perform scaling transformation to the triangle with vertices A (6, 9), B (10, 5), C (4, 3) with scaling factors Sx = 3 and Sy = 2. [Show the necessary transformation matrix]
Scaling about the origin multiplies each coordinate: x' = Sx·x, y' = Sy·y.
Scaling matrix (homogeneous): with Sx = 3, Sy = 2
S = | 3 0 0 |
| 0 2 0 |
| 0 0 1 |
The vertices as columns of the matrix P, and P' = S · P:
A B C A' B' C'
P = | 6 10 4 | P' = | 18 30 12 |
| 9 5 3 | | 18 10 6 |
| 1 1 1 | | 1 1 1 |
Step by step:
A(6,9): x' = 3×6 = 18, y' = 2×9 = 18
B(10,5): x' = 3×10 = 30, y' = 2×5 = 10
C(4,3): x' = 3×4 = 12, y' = 2×3 = 6
Answer: A'(18, 18), B'(30, 10), C'(12, 6). The triangle is enlarged 3 times in x and 2 times in y, and since scaling is about the origin, it also moves away from the origin.
✓ Answer checked by Claude Opus 5.5 (high effort)
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